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jok3333 [9.3K]
3 years ago
9

What is accretion?????

Chemistry
2 answers:
Monica [59]3 years ago
8 0

Answer:

the process of growth or increase, typically by the gradual accumulation of additional layers or matter.

Explanation:

nasty-shy [4]3 years ago
4 0

Answer:

The process of growth or increase, typically by the gradual accumulation of additional layers or matter.

Explanation:

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A very small country that has managed to stay independent of their larger neighbors. (Example: Vatican City)
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First option (Independent State)

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3 years ago
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4. How many atoms are in 32.6 g of Oxygen?
Natali5045456 [20]

Hey there!

Oxygen has a molar mass of 16. That means 16g of oxygen is 1 mole.

32.6 ÷ 16 = 2.0375 moles

We have 2.0375 moles.

There are 6.022 x 10²³ atoms in one mole.

2.0375 x 6.022 x 10²³

1.3 x 10²⁴

There are 1.3 x 10²⁴ atoms in 32.6 grams of oxygen.

Hope this helps!

7 0
3 years ago
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What volume of a 0.200 M HCI solution is needed to neutralize 25.0 L of a 0.250 M NaOH solution? Follow these steps
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Answer: A little bit confused can you explain what I have to do

Explanation:

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2 years ago
What are some real world applications in which ph is an important factor?
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Medications for skin , and medication for babies
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A student performs the reduction of 4-nitrobenzaldehyde (151.12 g/mol) with sodium borohydride (37.83 g/mol) in the presence of
Leviafan [203]

Answer:

65.4%

Explanation:

The redox reaction is a 1:1:1 reaction because the reagents suffer a double displacement reaction, and the substance that is substituted have the same charge (H+ and Br-), thus, we first need to know which of the reagents is the limiting.

Let's test the 4-nitrobenzaldehyde as the limiting. The mass needed for sodium borohydride (m) is the mass given of 4-nitrobenzaldehyde multiplied by the stoichiometric mass of sodium borohydride divided by the stoichiometric mass of 4-nitrobenzaldehyde. The stoichiometric mass is the number of moles in the stoichiometric representation (1:1:1) multiplied by the molar mass, so:

m = (4.13 * 37.83*1)/(151.12*1)

m = 1.034 g

So, the mass needed of the other reagent is larger than the mass that was given, so, it will be the limiting, and the stoichiometric calculus must be done with it.

The mass of the product that was expected is then:

m = (0.700*153.14*1)/(37.83*1)

m = 2.83 g

The percent yield is the mass that was formed divided by the expected mass, and then multiplied by 100%:

%yield = (1.85/2.83)*100%

%yield = 65.4%

8 0
3 years ago
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