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elixir [45]
3 years ago
12

A one or two letter abbreviation for a chemical element is called

Chemistry
2 answers:
Harrizon [31]3 years ago
7 0

chemical symbol

hope this helps

slega [8]3 years ago
5 0

Answer:

A symbol

Explanation:

<em>A symbol is an abbreviation</em> for a chemical element. These symbols comprise one or two letters, the first letter being a capital letter. These symbols could either be of Latin, Greek or English origin, depending on when the element was discovered.

Symbols for elements having origins other than English were discovered much earlier while those of English origin were more recently discovered. Examples of symbols for chemical elements include <em>NI for Nickel, O for oxygen, LI for lithium and Pb for Lead.</em>

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What is the concentration of bromide, in ppm, if 12.41 g MgBr2 is dissolved in 2.55 L water.
pav-90 [236]

Answer:

concentration of bromide (Br⁻) = 4234 mg/L = 4234 ppm

Explanation:

ppm (parts per million) concentration is defined as the mass (in milligrams) of a substance dissolved in one liter of solution.

In our case we have:

mass of MgBr₂ = 12.41 g

volume of water (which is equal to the final solution volume) = 2.55 L

Now we devise the following reasoning:

if         12.41 g of MgBr₂ are dissolved in 2.55 L of water

then         X g of MgBr₂ are dissolved in 1 L of water

X = (1 × 12.41) / 2.55 = 4.867 g of MgBr₂

if in         184 g (1 mole) of MgBr₂ we have 160 g of Br⁻

then in   4.867 g of MgBr₂ we have Y g of Br⁻

Y = (4.867 × 160) / 184 = 4.232 g of bromide (Br⁻)

4.232 g of bromide (Br⁻) = 4234 mg of bromide (Br⁻)

concentration of bromide (Br⁻) = 4234 mg/L = 4234 ppm

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Explanation:

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When electrons gain energy, what can they do?
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A 13.00 g sample of citric acid reacts with an excess of baking soda What is the theoretical yield of carbon dioxide
viva [34]

Answer:

8.934 g

Step-by-step explanation:

We know we will need a balanced equation with masses and molar masses, so let’s gather all the information in one place.  

M_r:        192.12                                                                   44.01

            H₃C₆H₅O₇ + 3NaHCO₃ ⟶ Na₃C₆H₅O₇ + 3H₂O + 3CO₂

m/g:        13.00

For ease of writing, let's write H₃C₆H₅O₇ as H₃Cit.

(a) Calculate the <em>moles of H₃Cit </em>

n = 13.00 g  × (1 mol H₃Cit /192.12 g H₃Cit)

n = 0.067 67 mol H₃Cit

(b) Calculate the <em>moles of CO₂ </em>

The molar ratio is (3 mol CO₂/1 mol H₃Cit)

n = 0.067 67 mol H₃Cit × (3 mol CO₂/1 mol H₃Cit)

n = 0.2030 mol CO₂

(c) Calculate the <em>mass of CO₂ </em>

m = 0.2030 mol CO₂ × (44.01 g CO₂/1 mol CO₂)

m = 8.934 g CO₂

4 0
4 years ago
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