After thorough researching, the Keq for the reaction N2 + 3H2 2NH3 if the equilibrium concentrations are [NH3] = .250 M, [N2] = .590 M, and [H2] = .750 M is 1.33. The correct answer to the following given statement above is 1.33
Answer:
See explanation
Explanation:
I believe that the aim of the scientist is to determine the effect of a cancer drug on mice with lymphoma. In this experiment, the mice with lymphoma are exposed to the drug. This is the treatment in the experiment. A control group of mice having lymphoma is not exposed to this treatment, this is the control group. This control group establishes a baseline for the study.
By comparing the outcome of the experimental and control groups, the effect of a cancer drug on mice with lymphoma can be determined.
Answer:
Energy lost is 7.63×10⁻²⁰J
Explanation:
Hello,
I think what the question is requesting is to calculate the energy difference when an excited electron drops from N = 15 to N = 5
E = hc/λ(1/n₂² - 1/n₁²)
n₁ = 15
n₂ = 5
hc/λ = 2.18×10⁻¹⁸J (according to the data)
E = 2.18×10⁻¹⁸ (1/n₂² - 1/n₁²)
E = 2.18×10⁻¹⁸ (1/15² - 1/5²)
E = 2.18×10⁻¹⁸ ×(-0.035)
E = -7.63×10⁻²⁰J
The energy lost is 7.63×10⁻²⁰J
Note : energy is lost / given off when the excited electron jumps from a higher energy level to a lower energy level
it is silver oxide my friend mark as brainlest t
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silver oxide
Silver oxide is the chemical compound with the formula Ag₂O. It is a fine black or dark brown powder that is used to prepare other silver compounds
Answer:
10.4664 grams of CO
Explanation:
Remark
There's a couple of things you must look out for in this question.
1. The use of the term atoms. There are 2 atoms in each mol of CO
2. You need to divide by 2 to find the number of molecules which will lead to moles.
<u>Step one</u>
Divide the number of atoms by 2
4.50 e^23 / 2 atoms = 2.25 * 10^23 molecules.
<u>Step Two</u>
Find the number of moles of CO
1 mol of anything is 6.02 * 10^23 molecules in this case
x = 2.25 * 10^23 molecules
1/x = 6.02 * 10^23/2.25 * 10 ^23 Cross multiply
1 * 2.25 * 10^23 = 6.02*10^23 * x Divide by 6.02 * 10^23
2.25 * 10 ^ 23 / 6.02 * 10^23 = x
x = .3738 moles of CO
<u>Step Three</u>
Find the gram molecular mass of CO
C = 12
O = 16
1 mole = 12 + 16 = 28 grams.
<u>Step Four</u>
Find the number of gram in 0.3738 mols
1 mol = 28 grams
0.3738 mol = x Cross multiply
x = 28 * 0.3738
x = 10.4664 grams