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2 years ago

Science please helppp

Physics

1 answer:

Daniel [21]2 years ago

3 0

The red box must way more. Gravitational potential energy is the product of a an objects mass times the acceleration due to gravity (which is constant on earth) times its height. Since the objects are on the same shelf they are at the same height, and since gravitational acceleration is constant as long as we stay on planet earth, then the mass is the only possible thing that could have changed. This means that the red box must weigh more than the blue box.

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A 1.00-kg object is attached by a thread of negligible mass, which passes over a pulley of negligible mass, to a 2.00-kg object.

Anna [14]

Answer:

a = 3.27 m/s²

v = 2.56 m/s

Explanation:

given,

mass A = 1 kg

mass B = 2 kg

vertical distance between them = 1 m

$F_d = mg$

$F_d = 2 \times 9.8$

$F_d = 19.6\ N$

$F_u = mg$

$F_u = 1 \times 9.8$

$F_u = 9.8\ N$

$F_{net} = 19.6 - 9.8$

$F_{net}=9.8\ N$

$F = (m_1+m_2)a$

$9.8 = (2+1)a$

a = 3.27 m/s²

The speed of the system at that moment is:

v² = u² + 2×a×s

v² = 0² + 2× 3.27 × 1

v ² = 6.54

v = 2.56 m/s

3 0

2 years ago

2) 1. A vibration of an electric charge.

Anestetic [448]

Explanation:

<h2> Answers</h2>

1.Electromagnetic waves

2.Electromagnetic radiation

3.Electromagneticwaves

5 0

2 years ago

Concept Simulation 20.4 provides background for this problem and gives you the opportunity to verify your answer graphically. Ho

77julia77 [94]

Answer:

The time constant is 1.049.

Explanation:

Given that,

Charge $q{t}= 0.65 q_{0}$

We need to calculate the time constant

Using expression for charging in a RC circuit

$q(t)=q_{0}[1-e^{-(\dfrac{t}{RC})}]$

Where, $\dfrac{t}{RC}$ = time constant

Put the value into the formula

$0.65q_{0}=q_{0}[1-e^{-(\dfrac{t}{RC})}]$

$1-e^{-(\dfrac{t}{RC})}=0.65$

$e^{-(\dfrac{t}{RC})}=0.35$

$-\dfrac{t}{RC}=ln (0.35)$

$-\dfrac{t}{RC}=-1.049$

$\dfrac{t}{RC}=1.049$

Hence, The time constant is 1.049.

6 0

2 years ago

2.2.4 Quiz: Conservation of Energy

dexar [7]

Answer:

it is the judicious use of energy to prevent wastage

7 0

2 years ago

A square current-carrying loop is placed in a uniform magnetic field B with the plane of the loop parallel to the magnetic field

Radda [10]

Answer:

(A) a net torque but no net force on the loop.

Explanation:

The total force on the loop is zero because the forces on the opposite sides of the loop are equal but act in opposite directions and as a result they cancel each other out. The two forces on opposite sides to the axis of rotation each give rise to a torque about the axis of rotation. This torque is directed along the axis of rotation.

5 0

3 years ago