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3 years ago

Classify each of the following items as a rigid body, a system of rigid bodies, or a nonrigid body:

Physics

1 answer:

KatRina [158]3 years ago

5 0

Answer:

Rigid bodies: Options d and e

Rigid bodies' system: options f, g and h

Non-rigid bodies: Options a, b and c

Explanation:

The above classification of the mentioned objects into rigid bodies, non rigid bodies and system of rigid bodies can be explained as :

Rigid body: A body which does not undergo any change in its form or shape on application of externally applied load or force is said to be a rigid body.

System of Rigid bodies:

A system of rigid bodies is different from any other element system as in this the bodies constituting the system must be rigid bodies.

Non-rigid bodies:

A body which undergoes a change in its form or shape on application of externally applied force or load is said to be a non-rigid body.

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Please help on this one?

bezimeni [28]

Using the given equation you get:

E = 1.99x10^-25 / 9.0x10^-6

Divide 1.99 by 9.0: 1.99/9.0 = 0.22

For the scientific notation, when dividing subtract the two exponents:

25 -6 = 19

So you now have 0.22 x 10^-19

Now you need to change the 0.22 to be in scientific notation form:

2.2 x 10^-20

The answer is B.

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2 years ago

A 64.8 kg astronaut is on a space walk when the tether line to the shuttle breaks. The astronaut is able to throw a 11.0 kg oxyg

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3 years ago

A solenoidal coil with 26 turns of wire is wound tightly around another coil with 350 turns. The inner solenoid is 20.0 cm long

noname [10]

Answer:

Part a)

$\phi = 2.76 \times 10^{-7} T m^2$

Part B)

$M = 5.52 \times 10^{-5} H$

Part C)

$EMF = 0.1 V/s$

Explanation:

Part a)

Magnetic field due to a long ideal solenoid is given by

$B = \mu_0 n i$

n = number of turns per unit length

$n = \frac{N}{L}$

$n = \frac{350}{0.20}$

$n = 1750 turn/m$

now we know that magnetic field due to solenoid is

$B = (4\pi \times 10^{-7})(1750)(0.100)$

$B = 2.2 \times 10^{-4} T$

Now magnetic flux due to this magnetic field is given by

$\phi = B.A$

$\phi = (2.2 \times 10^{-4})(\pi r^2)$

$\phi = (2.2 \times 10^{-4})(\pi(0.02)^2)$

$\phi = 2.76 \times 10^{-7} T m^2$

Part B)

Now for mutual inductance we know that

$\phi_{total} = M i$

$\phi_{total} = N\phi$

$\phi_{total} = 20(2.76 \times 10^{-4})$

$\phi_{total} = 5.52 \times 10^{-6}$

now we have

$M = \frac{5.52 \times 10^{-6}}{0.100}$

$M = 5.52 \times 10^{-5} H$

Part C)

As we know that induced EMF is given as

$EMF = M \frac{di}{dt}$

$EMF = 5.52 \times 10^{-5} (1800)$

$EMF = 0.1 V/s$

3 0

3 years ago

PLEASE HELP it takes tsooo long! lol ima fail! please help! thanks!

Natasha_Volkova [10]

Answer:

A and c, hope i helped xx

Explanation:

4 0

3 years ago

Read 2 more answers

En un juego de béisbol, un lanzador logra

den301095 [7]

Answer:

B transferred.

Explanation:

The kinetic energy is simply transferred by transforming it into other forms of energy.

According to the law of conservation of energy "energy is neither created nor destroyed but transformed from one form to another".

The moving baseball posses kinetic energy
As it hits the bat, it is converted to mechanical and thermal energy.
The bat warms up due to the transfer of the kinetic energy.
The mechanical energy of the bat cause work to be done on it and it breaks apart.
This ensures that the energy in this process is conserved.

7 0

3 years ago