There are 10 balls in the Urn Total.
Red: 6
Green: 4
Question One: The probability that five red and two green is selected is likely. (as that is over half for both)
Question Two: Impossible. There is only 6 red balls, and 7 are taken from the urn. Thus it would at most be possible for 6 red and 1 green.
Question Three: At least four is likely, as there is more red then green in the Urn.
Hope I helped!
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Answer: SAS
Step-by-step explanation:
There is an angle B or D and the sides being the 26, 21, and 32! (Sorry if I get it wrong)
Answer:
The answer is 6.
Step-by-step explanation:
If there are 270 students going on the trip and there would be a teacher for every 45 students you would have to divide.
You would divide 270 ÷ 45 = 6.
3(k-x)= -3x-9
3k - 3x = -3x - 9 ← equation without parentheses
3k - 3x + 3x = - 9
3k = -9
k = -9/3
k = -3 ← simplest form