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Monica [59]
3 years ago
7

Suppose you lived in the crater Copernicus on the side of the Moon facing Earth.

Physics
1 answer:
Wittaler [7]3 years ago
5 0

Answer and Explanation:

In case, I lived in the Crater Copernicus on Moon's side facing the Earth then:

  • On moon, as it orbits the Earth, it takes 29 and a half days to complete one cycle of sunrise and sunset. So, the would rise once in 29 and a half day.
  • The moon orbits the Earth in such a way that the its same side faces the Earth always which concludes that the Earth is overhead every time resulting in no Earth rise or Earth set on Moon.
  • Due to the thin atmosphere, it can't impart any specific color to the sky on the moon as a result of which the moon's sky is always black and hence, stars can be seen every time.

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A mason is shot with a constant speed of 7.5 x 10²m/sinto a region, when an electric field produces acceleration on the mason of
nadya68 [22]

Answer:

Distance, d = 0.1 m

It is given that,

Initial velocity of meson,

Finally, the meson is coming to rest v = 0

Acceleration of the meson,  (opposite to initial velocity)

Using third equation of motion as :

s is the distance the meson travelled before coming to rest.

So,

 

s = 0.1 m

The meson will cover the distance of 0.1 m before coming to rest. Hence, this is the required solution.  

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2 years ago
What does x repressent on a motion map?​
Gnoma [55]

Answer:

The x represents the reference point on a motion map

Explanation:

-Motion maps are another way to represent the motion of an object. (other representations are graphical and mathematical models)

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2 years ago
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3 A 100 g steel ball falls from a height of 1.8 m on to a metal plate and rebounds to a height of 1.25 m.​
BigorU [14]

Given values:

Mass of the steel ball, m = 100 g = 0.1 kg

Height of the steel ball, h1 = 1.8 m

Rebound height, h2 = 1.25 m

a.  PE= mgh

0.1 x 9.8 x 1.8 =

1.764 Joules

b. KE = PE ->

1.764 Joules

c. KE= 1/2 mv square

so v = square root 2ke/m

square root 2 x 1.764/ 0.1

= 5.93 m/s

d. KE=PE=mgh square

0.1 x 9.8 x 1.21 =

1.186 joules

velocity of rebond is square root 2x 1.186/ 0.1 = 4.87 m/s

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Your friend provides a solution to the following problem. Evaluate her solution. The problem: Jim (mass 50 kg) steps off a ledge
Mekhanik [1.2K]

Answer:

No its wrong

Correct compression is 0.41

Explanation:

After jumping from 2m height on spring attached platform platform is compressed a distance x(let).

So work done by gravity on Jim is converted into spring potential energy.

k=8000 N/m

mass of Jim =50 kg

\frac{1}{2}k(x)^{2} =m*g(2+x)

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8.16x^{2} =2 +x

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