Use the formula. Plug in known values, so you get f = 3000*2 and get 6000N as a result.
Answer:
Option B
3
Explanation:
The two dimensions have the following significant numbers
4.56- 3 significant numbers
5.668- 4 significant figures
When responding, we give area as per the most precise number given hence the smallest (most precise) significant figures in these two numbers is 3. Therefore, the area will be given to 3 significant figures ie
4.56*5.668=25.84608 square meters
Area=25.8 square meters
The correct answer would be C because declining a break from exercise is considered overload.
Answer:
a. 340.13 m/s b. 680.26 m/s c. our wavelength doubles
Explanation:
a. speed of wave, v = fλ were f = frequency = 301 Hz and λ = wavelength = 1.13 m.
v = fλ = 301 Hz × 1.13 m = 340.13 m/s
b. If we double the frequency then f = 2 × 301 Hz = 602 Hz
v = fλ = 602 Hz × 1.13 m = 680.26 m/s
c. If the speed of the wave is still 340.13 m/s, if we cut the frequency in half, then frequency now equals f = 301 Hz/2 = 150.5 Hz.
Since v = fλ,
λ = v/f = 340.13 m/s ÷ 150.5 Hz = 2.26 m.
Since our initial wavelength λ₀ = 1.13 m,
λ/λ₀ = 2.26 m/1.13 m = 2.
So, λ = 2λ₀ our wavelength doubles
To answer the problem we would be using this formula which is I(peak) = P(peak)/(4πd^2) = 4.24413181578388 w/m^2
E = sqrt(I(peak)*Z0) = 39.9861614728793 V/m
B = µ0*sqrt(I(peak)/Z0) = 1.33379477721328E-7 T
(Free-space impedance Z0 = sqrt(µ0/e0) = 376.730313462204 ohms)