1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vlada-n [284]
3 years ago
9

What is the relationship between atmospheric pressure and the density of gas particles in an area of decreasing pressure? (2 poi

nts)
A. As air pressure in an area decreases, the density of the gas particles in that area decreases.
B. As air pressure in an area decreases, the density of the gas particles in that area increases.
C. As air pressure in an area decreases, the density of the gas particles in that area remains constant.
D. As air pressure in an area decreases, the density of the gas particles in that area increases and decreases in an alternating pattern.

Also it's not showing earth space science, so that's why I put it as Physics.
Physics
2 answers:
Effectus [21]3 years ago
8 0

Answer:

As air pressure in an area decreases, the density of the gas particles in that area decreases.

Explanation:

ivann1987 [24]3 years ago
4 0

Answer:

A. As air pressure in an area decreases, the density of the gas particles in that area decreases.

Explanation:

At constant temperature, pressure and density of a gas are directly related.  So if pressure decreases, density decreases.

You might be interested in
Even when the head is held erect, as in the figure below, its center of mass is not directly over the principal point of support
alexandr1967 [171]

We are asked to determine the force required by the neck muscle in order to keep the head in equilibrium. To do that we will add the torques produced by the muscle force and the weight of the head. We will use torque in the clockwise direction to be negative, therefore, we have:

\Sigma T=r_{M\perp}(F_M)-r_{W\perp}(W)

Since we want to determine the forces when the system is at equilibrium this means that the total sum of torque is zero:

r_{M\perp}(F_M)-r_{W\perp}(W)=0

Now, we solve for the force of the muscle. First, we add the torque of the weight to both sides:

r_{M\perp}(F_M)=r_{W\perp}(W)

Now, we divide by the distance of the muscle:

(F_M)=\frac{r_{W\perp}(W)}{r_{M\perp}}

Now, we substitute the values:

F_M=\frac{(2.4cm)(50N)}{5.1cm}

Now, we solve the operations:

F_M=23.53N

Therefore, the force exerted by the muscles is 23.53 Newtons.

Part B. To determine the force on the pivot we will add the forces we add the vertical forces:

\Sigma F_v=F_j-F_M-W

Since there is no vertical movement the sum of vertical forces is zero:

F_j-F_M-W=0

Now, we add the force of the muscle and the weight to both sides to solve for the force on the pivot:

F_j=F_M+W

Now, we plug in the values:

F_j=23.53N+50N

Solving the operations:

F_j=73.53N

Therefore, the force is 73.53 Newtons.

8 0
11 months ago
Which of the following must be true about the object labeled X in the circuit below?
Alex787 [66]

the answer is c and if I help you  thank me
4 0
3 years ago
A car is moving in uniform circular motion. If the cars speed were to double to keep the car moving with the same radius the acc
Stells [14]

Answer:

<em>The centripetal acceleration would increase by a factor of 4</em>

<em>Correct choice: B.</em>

Explanation:

<u>Circular Motion</u>

The circular motion is described when an object rotates about a fixed point called center. The distance from the object to the center is the radius. There are other magnitudes in the circular motion like the angular speed, tangent speed, and centripetal acceleration. The formulas are:

v_t=w\ r

\displaystyle a_c=\frac{v_t^2}{r}

If the speed is doubled and the radius is the same, then

\displaystyle a_c=\frac{(2v_t)^2}{r}

\displaystyle a_c=4\frac{v_t^2}{r}

The centripetal acceleration would increase by a factor of 4

Correct choice: B.

5 0
3 years ago
What does the voltage-current graph above show about the relationship between voltage and current, and how do these properties a
zubka84 [21]

The answer is as voltage increases current increases and therefore resistance would remain constant

4 0
3 years ago
I. What is the initial velocity of the car?
qaws [65]

Answer:

I. 0 m/s

II. 20 m/s

III. Part BC

Explanation:

I. Determination of the initial velocity.

From the diagram given above,

The motion of the car starts from the origin. This implies that the car start from rest and as such, the initial velocity of the car is 0 m/s

II. Determination of the maximum velocity attained.

From the diagram given above, we can see clearly that the maximum velocity is 20 m/s.

III. Determination of the part of the graph that represents zero acceleration.

It important that we know the meaning of zero acceleration.

Zero acceleration simply means the car is not accelerating. This can only be true when the car is moving with a constant velocity.

From the graph given above, the car has a constant velocity between B and C.

Therefore, part BC illustrates zero acceleration.

6 0
3 years ago
Other questions:
  • In April 1974, Steve Prefontaine completed a 10.0 km race in a time of 27 min , 43.6 s . Suppose "Pre" was at the 7.43 km mark a
    12·1 answer
  • a conical pendulum is formed by attaching a 50g mass to a 1.2m string. The mass swings around the circle of radius 25cm (a) calc
    5·1 answer
  • A 7.9 g bullet leaves the muzzle of a rifle with ayvaci (na25565) – Chapter 4 Basics – balantic – (APPhysPd4Balant) 2 a speed of
    7·1 answer
  • Is the study of muscle movements in the human body an example of biology
    11·1 answer
  • What scenarios best describes how the hawaiian islands formed in the pacific ocean?
    5·1 answer
  • Difference between cold and warm blooded animal.
    12·1 answer
  • 1. Which of the following is true about sound waves?
    13·1 answer
  • Last week Tasha and Amy got into a fight at school. Tasha is accusing Amy of talking behind her back. Since the fight, Tasha has
    9·2 answers
  • A car is traveling at 30 m/s ( approximately 67 mph) on I-95 highway. The driver applies the brakes and the car comes to a stop
    14·1 answer
  • The students on the right are applying a force of 100 N to the right. This is shown by the red arrow. The students on the left a
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!