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vlada-n [284]
3 years ago
9

What is the relationship between atmospheric pressure and the density of gas particles in an area of decreasing pressure? (2 poi

nts)
A. As air pressure in an area decreases, the density of the gas particles in that area decreases.
B. As air pressure in an area decreases, the density of the gas particles in that area increases.
C. As air pressure in an area decreases, the density of the gas particles in that area remains constant.
D. As air pressure in an area decreases, the density of the gas particles in that area increases and decreases in an alternating pattern.

Also it's not showing earth space science, so that's why I put it as Physics.
Physics
2 answers:
Effectus [21]3 years ago
8 0

Answer:

As air pressure in an area decreases, the density of the gas particles in that area decreases.

Explanation:

ivann1987 [24]3 years ago
4 0

Answer:

A. As air pressure in an area decreases, the density of the gas particles in that area decreases.

Explanation:

At constant temperature, pressure and density of a gas are directly related.  So if pressure decreases, density decreases.

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A spherical balloon has a radius of 6.95 m and is filled with helium. The density of helium is 0.179 kg/m3, and the density of a
Aleks [24]

volume of balloon

= 4/3 T R3

= 4/3 x 3.14 x 6.953

= 1405.47 m3

uplift force

= volume of balloon x density of air x 9.8

= = 1405.47 x 1.29 x 9.8

= 1813.05 x 9.8 N

weight of helium gas

= volume of balloon x density of helium x

9.8

= 1405.47 x .179 x 9.8

= 251.58 x 9.8 N

Weight of other mass = 930 x 9.8 N Total weight acting downwards

= 251.58 x 9.8 +930 x 9.8

= 1181.58 x 9.8 N

If W be extra weight the uplift can balance

1181.58 × 9.8 + W × 9.8 = 1813.05 * 9.8

1181.58+W=1813.05

W= 631.47 kg

3 0
2 years ago
An spring has a period of 4 seconds. What is its frequency?
trasher [3.6K]

Answer:

2Hz

Explanation:

Hope this helps

7 0
3 years ago
The diver uses compressed air to breathe under water. 1700 litres of air from the atmosphere is compressed into a 12-litre gas c
ivann1987 [24]

Answer:

The answer is below

Explanation:

A diver works in the sea on a day when the atmospheric pressure is 101 kPa. The diver uses compressed air to breathe under water. 1700 litres of air from the atmosphere is compressed into a 12-litre gas cylinder. The compressed air quickly cools to its original temperature. Calculate the pressure of the air in the cylinder.

Solution:

Boyles law states that the volume of a given gas is inversely proportional to the pressure exerted by the gas, provided that the temperature is constant.

That is:

P ∝ 1/V;   PV = constant

P₁V₁ = P₂V₂

Given that P₁ = initial pressure = 101 kPa, V₁ = initial volume = 1700 L, P₂ = cylinder pressure, V₂ = cylinder volume = 12 L. Hence:

P₁V₁ = P₂V₂

100 kPa * 1700 L = P₂ * 12 L

P₂ = (100 kPa * 1700 L) / 12 L

P₂ = 14308 kPa

6 0
2 years ago
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