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TEA [102]
2 years ago
15

Banked Curves: A 600-kg car is going around a banked curve with a radius of 110 m at a steady speed of 24.5 m/s. What is the app

ropriate banking angle so that the car stays on its path without the assistance of friction
Physics
1 answer:
Aleks04 [339]2 years ago
8 0

The angle of baking from the calculation is obtained as 30°.

<h3>What is banking?</h3>

The term banking refers to a means of preventing vehicles from skidding off the road at curves.

We know that the banking angle is obtained from;

θ = tan-1(v^2/rg)

v = 24.5 m/s

r = 110 m

g = 9.8 m/s^2

θ = tan-1(25^2/9.8 * 110)

θ = tan-1(625 /1078)

θ = 30°

Learn more about the banking angle:brainly.com/question/26759099?r

#SPJ1

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A wheel rotates without friction about a stationary horizontal axis at the center of the wheel. A constant tangential force equa
ivann1987 [24]

Answer:

The moment of inertia of the wheel is 0.593 kg-m².

Explanation:

Given that,

Force = 82.0 N

Radius r = 0.150 m

Angular speed = 12.8 rev/s

Time = 3.88 s

We need to calculate the torque

Using formula of torque

\tau=F\times r

\tau=82.0\times0.150

\tau=12.3\ N-m

Now, The angular acceleration

\dfrac{d\omega}{dt}=\dfrac{12.8\times2\pi}{3.88}

\dfrac{d\omega}{dt}=20.73\ rad/s^2

We need to calculate the moment of inertia

Using relation between torque and moment of inertia

\tau=I\times\dfrac{d\omega}{dt}

I=\dfrac{I}{\dfrac{d\omega}{dt}}

I=\dfrac{12.3}{20.73}

I= 0.593\ kg-m^2

Hence, The moment of inertia of the wheel is 0.593 kg-m².

5 0
3 years ago
What is the order of magnitude of the gravitational force between two 1.0 kilogram charges that are positioned 1.0 meter apart?
stiks02 [169]

The answer is  -11

Enjoy!

6 0
3 years ago
Calculate the average speed of the moon around the earth. The moon has a period of revolution of 27.3 days and an average distan
klio [65]
<h2>The average speed of the moon around the earth is 1021.74 m/s</h2>

Explanation:

Radius of moon around earth, r = 3.84 × 10⁸ m

Circumference of orbit = 2πr = 2 x 3.14 x 3.84 × 10⁸

Circumference of orbit = 2.41 x 10⁹ m

Time taken, t = 27.3 days = 27.3 x 24 x 60 x 60 = 2358720 seconds

We have

       Circumference of orbit = Speed of moon x Time taken

        2.41 x 10⁹ = Speed of moon x 2358720

       Speed of moon = 1021.74 m/s

The average speed of the moon around the earth is 1021.74 m/s

5 0
3 years ago
The position-time graph describes the motion of a moving object. Describe the motion represented by each segment of the graph.
Marrrta [24]

Answer:

to much sorry.

Explanation:

3 0
3 years ago
A 70.0 kg ice hockey goalie, originally at rest, has a 0.110 kg hockey puck slapped at him at a velocity of 31.5 m/s. Suppose th
NISA [10]

Answer

given,

mass of the goalie(m₁) = 70 kg

mass of the puck (m₂)= 0.11 kg

velocity of the puck = 31.5 m/s

elastic collision

v_1=\dfrac{m_2-m_1}{m_1+m_2}v_1+\dfrac{2m_2}{m_1+m_2}v_2

v_{pf}=\dfrac{0.11-70}{0.11+70}31.5+\dfrac{2m_2}{m_1+m_2}\times (0)

v_{pf}=-31.4\ m/s

v'_2 = \dfrac{2m_1v_1}{m_1+m_2}-\dfrac{(m_2-m_1)v_2}{m_2+m_1}

v_{gf} = \dfrac{2\times 0.11\times 31.5}{0.11+70}-\dfrac{(0.11-70)\times 0}{m_1+m_2}

v_{gf} = \dfrac{2\times 0.11\times 31.5}{0.11+70}

v_{gf} = 0.0988\ m/s

4 0
3 years ago
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