All the points that are 6 units from (-1, 1) are those on the circle
(x+1)^2 +(y-1)^2 = 36
For y=0, the two points of interest satisfy
(x+1)^2 +1 = 36
(x+1)^2 = 35 . . . . . . subtract 1
x+1 = ±√35
x = -1±√35
The points you seek are
(-1-√35, 0) and (-1+√35, 0), about (-6.916, 0) and (4.916, 0).
Answer:
22
Step-by-step explanation:
To solve this we can plug the values in.
-2x-3y+z
-2(4)-3(-7)+(9)
Simplify.
-8+21+9
Add.
22
Answer:
Up up up up up up up up up up
We can use the points (-6, 2) and (-4, 13) to solve.
Slope formula: y2-y1/x2-x1
= 13-2/-4-(-6)
= 11/2
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Best Regards,
Wolfyy :)