Question

deepta and abhinav having weight 450N and 350N are playing seesaw. If deepta sits at a distance of 2cm from fulcrum, how far should abhinav be seated in order to balance deepta?​

Answer 1

Answer:

Abhinav be seated at "2.57 cm" far. The further explanation is given below.

Explanation:

The given values are:

Deepta's weight,

= 450 N

Abhinav's weight,

= 350 N

Deepta's distance from fulcrum,

= 2cm

i.e.,

= 0.02 m

Let Abhinav's distance be "x".

As we know,

⇒  $Work \ done \ by \ Deepta = Work \ done \ by \ Abhinav$

⇒  $Deepta's \ weight\times Deepta's \ distance = Abhinav's \\ weight\times Abhinav's \ distance$

⇒  $450\times 0.02=350\times x$

⇒  $9=350\times x$

⇒  $\frac{9}{350} = x$

⇒  $x=0.025 \ m$

i.e.,

⇒  $2.57 \ cm$