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trasher [3.6K]
3 years ago
8

This is the picture answer this plsss..

Chemistry
1 answer:
Ulleksa [173]3 years ago
3 0

Answer:

he is a weelder because of him taking a peice of metal and recreateing it.

Explanation:

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An ion of iron has an 26 protons, 30 neutrons, and 23 electrons. What are its atomic number, atomic mass, and net charge?
sleet_krkn [62]

Answer:

Atomic number 26,atomic mass 26+30=56 dalton and net charge is 3+

Explanation:

The total number of proton present in an atom is known as the atomic number of that atom.From that point of view the atomic number of iron ion is 26.

  The total number proton and neutrons present in the nucleus of an atom or ion is termed as atomic mass.From that point of view the the atomic mass of iron ion is 26+30=56 dalton

 According to the given question iron ion contain 3 more protons than electrons as a result the iron ion will contain 3 unit positive charge.

5 0
3 years ago
Balanced equation for Co+O2=Co2O3
Reptile [31]

Answer:

4 Co(s) + 3 O2(g) = 2 Co2O3(s)

Explanation:

6 0
3 years ago
An element’s atomic number is the?
Cloud [144]
G'day love! An elements atomic number is the amount of protons in an element!
7 0
3 years ago
Read 2 more answers
What is the pH of solution if the concentration of [H3O+] = 0.000558?
lina2011 [118]

Answer:

3.25

Explanation:

pH = -log[H3O+]

-log(0.000558)=3.25

7 0
4 years ago
(4) Calculate the % of a compound that can be removed from liquid phase 1 by using ONE to FOUR extractions with a liquid phase 2
maksim [4K]

Answer:

One extraction: 50%

Two extractions: 75%

Three extractions: 87.5%

Four extractions: 93.75%

Explanation:

The following equation relates the fraction q of the compound left in volume V₁ of phase 1 that is extracted n times with volume V₂.

qⁿ = (V₁/(V₁ + KV₂))ⁿ

We also know that V₂ = 1/2(V₁) and K = 2, so these expressions can be substituted into the above equation:

qⁿ = (V₁/(V₁ + 2(1/2V₁))ⁿ = (V₁/(V₁ + V₁))ⁿ =  (V₁/(2V₁))ⁿ = (1/2)ⁿ

When n = 1, q = 1/2, so the fraction removed from phase 1 is also 1/2, or 50%.

When n = 2, q = (1/2)² = 1/4, so the fraction removed from phase 1 is (1 - 1/4) = 3/4 or 75%.

When n = 3, q = (1/2)³ = 1/8, so the fraction removed from phase 1 is (1 - 1/8) = 7/8 or 87.5%.

When n = 4, q = (1/2)⁴ = 1/16, so the fraction removed from phase 1 is (1 - 1/16) = 15/16 or 93.75%.

5 0
3 years ago
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