Answer:
<h3>homeostasis</h3>
•the maintenance of a stable internal environment
<u><em>Hope </em><em>this</em><em> helps</em><em> </em><em>:</em><em>)</em></u>
Answer:
30 mL VOLUME OF 3.0 M HCl SHOULD BE USED BY THE STUDENT TO MAKE A 1.80 M IN 50 mL OF HCl.
Explanation:
M1 = 3.00 M
M2 = 1.80 M
V2 = 50 .0 mL = 50 /1000 L = 0.05 L
V1 = unknown
In solving this question, we know that number of moles of a solution is equal to the molar concentration multiplied by the volume. To compare two samples, we equate both number of moles and substitute for the required component.
So we use the equation:
M1 V1 = M2 V2
V1 = M2 V2 / M1
V2 = 1.80 * 0.05 / 3.0
V2 = 0.09 /3.0
V2 = 0.03 L or 30 mL
To prepare the sample of 1.80 M HCl in 50.0 mL from a 3.0 M HCl, 30 mL volume should be used.
Answer:
A and B is the answer as there structure change
What is it you need help on? there is nothing here????
ANSWER:
Answer:
Explanation:
Carboxylic acids is a homologous series in which the compounds contain a functional group called the carboxyl group (-COOH). The general molecular formula for carboxylic acids is CnH2n+1COOH. Carboxylic acids contain at least one carboxyl group.
Or in Polish…
Kwasy karboksylowe to homologiczna seria, w której związki zawierają grupę funkcyjną zwaną grupą karboksylową (-COOH). Ogólny wzór cząsteczkowy dla kwasów karboksylowych to CnH2n + 1COOH. Kwasy karboksylowe zawierają co najmniej jedną grupę karboksylową.
