9514 1404 393
Answer:
Step-by-step explanation:
The thrust of the question is to make sure you understand that increasing the y-coordinate of a point will move the point upward, and decreasing it will move the point downward.
That is adding a positive value "k" to x^2 will move the point (x, x^2) to the point (x, x^2+k), which will be above the previous point by k units.
If k is subtracted, instead of added, then the point will be moved downward.
The blanks are supposed to be filled with <u> positive </u>, and <u> negative </u>.
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<em>Comment on the question</em>
The wording of the statement you're completing is a bit odd. If k is negative (-2, for example), this statement is saying the graph is translated down -2 units. It is not. It is translated down |-2| = 2 units. The direction of translation depends on the sign of k. The amount of translation depends on the magnitude of k.
If you thoroughly understand (x, y) coordinates and how they are plotted on a graph, it should be no mystery that changing the y-coordinate will change the vertical position of the graph.
Answer:
answer is x=14.4.......,......
Answer:
$180 - (15% * $180) = $153
Step-by-step explanation:
Answer:
Find the value of x and y in coordinate form, that'll be the point of intersection.
Question 1

Therefore, points of intersection are two
Answer: <u> </u><u>(</u><u>3</u><u>,</u><u> </u><u>4</u><u>)</u><u> </u><u>and</u><u> </u><u>(</u><u>1</u><u>,</u><u> </u><u>2</u><u>)</u>
Question 2:
Following the steps as in question 1

Answer: <u>(2, 0)</u>
Answer:
m∠CBD = m∠CDB ⇒ proved
Step-by-step explanation:
Let us solve the question
∵ AB ⊥ BD ⇒ given
→ That means m∠ABD = 90°
∴ m∠ABD = 90° ⇒ proved
∵ ED ⊥ BD ⇒ given
→ That means m∠EDB = 90°
∴ m∠EDB = 90° ⇒ proved
∵ ∠ABD and ∠EDB have the same measure 90°
∴ m∠ABD = m∠EDB ⇒ proved
∵ m∠ABD = m∠ABC + m∠CBD
∵ m∠EDB = m∠EDC + m∠CDB
→ Equate the two right sides
∴ m∠ABC + m∠CBD = m∠EDC + m∠CDB
∵ m∠ABC = m∠EDC ⇒ given
→ That means 1 angle on the left side = 1 angle on the right side, then
the other two angles must be equal in measures
∴ m∠CBD = m∠CDB ⇒ proved