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Luden [163]
3 years ago
6

So which equation is (4, 3) a solution y= 2x-1y=3x-4y=2x-5y=x+3​

Mathematics
1 answer:
Oxana [17]3 years ago
4 0
Answer:
y=2x-5

Explanation:
Plug in the point into the equation
3=2(4)-5
3=8-5
3=3
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Find the area of the circle with the given radius or diameter. Use pi = 3.14. d = 10 A =
labwork [276]

The formula in computing the area of the circle is:

A = pi (r)^2

Where r = the radius of the circle

Since you are only given the diameter of the circle, you have to solve for its radius. The radius of the circle is half its diameter. Therefore, the radius of the circle is 5 (10/2).

Now, you substitute the measurements to the formula:

A = 3.14 (5)^2

A = 3.14 (25)

A = 78.5 sq. units

5 0
2 years ago
Read 2 more answers
What value for x will make the equation true?
Rama09 [41]

Answer:

C . 4

Step-by-step explanation:

step 1 : -3 multiply with inside of the ( 7x-5 )

= -21x + 15

step 2 : then it will be 21x + 15 = 87 + 3x

step 3 : switch between the odds into like this

21x - 3x = 87 - 15

step 4 : subtract it all

18x = 72

step 5 : bring 18 to the other side

x = 72/18

step 6 : to find the ans of x is just calculate them

x = 72 ÷ 18

= 4

Or you can do like these ⬇️

-3 ( 7x - 15 ) = 87 + 3x

21x + 15 = 87 + 3x

21x - 3x = 87 - 15

18x = 72

x = 72/18 or 72÷18

x = 4

4 0
2 years ago
An engineer is going to redesign an ejection seat for an airplane. the seat was designed for pilots weighing between 130lb and 1
Vlad [161]

Answer: 0.4758

Step-by-step explanation:

Given : Mean : \mu=137\text{ lb}

Standard deviation : \sigma =28.9\text{ lb}

Also, the new population of pilots has normally distributed .

The formula to calculate the z-score :-

z=\dfrac{x-\mu}{\sigma}

For x=130 lb .

z=\dfrac{130-137}{28.9}=-0.2422145\approx-0.24

For x=171lb.

z=\dfrac{171-137}{28.9}=1.1764705\approx1.18

The p-value =P(-0.24

=0.8809999-0.4051651=0.4758348\approx0.4758348\approx0.4758

Hence, the required probability : 0.4758

6 0
3 years ago
Percentage grade averages were taken across all disciplines at a particular university, and the mean average was found to be 83.
Paha777 [63]
Correct Answer:
Option A. 0.01

Solution:
This is a problem of statistics and uses the concept of normal distributions. We need to convert the score of 90 into z-score and then find the desired probability from standard normal distribution table.

Converting 90 to z-score:

z= \frac{90-83.6}{ \frac{8.7}{ \sqrt{10}} }=2.33

Now we are to find the probability of z score being more than 2.33. From the z-table the probability comes out to be 0.01.

Therefore, we can conclude that the probability of class average is greater than 90 is 0.01.
4 0
2 years ago
Find the slope of the line√3y-x-2√x​
expeople1 [14]
Please insert a picture of the question
5 0
3 years ago
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