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Verizon [17]
3 years ago
9

A lab is growing bacteria in a culture dish. The amount of bacteria in the dish doubles every 3 hours. Initially, there are 500

bacteria in the dish. How many are in the dish after 9 hours A. 4,500 B. 4,000 C. 1,500 D. 13,500
Mathematics
2 answers:
melomori [17]3 years ago
6 0
D- 500*3
 *3
 *3 =  13500
saveliy_v [14]3 years ago
3 0

Answer: B. 4,000

Step-by-step explanation:

Given: The initial amount of bacteria in the dish A= 500

Since, The amount of bacteria in the dish doubles every 3 hours.

The multiplicative rate of change after every 3 hours = 2

Time period = 3 hours

By exponential function, we have the amount of bacteria after time period 'x' is given by :-

y=Ab^x,  where A is the initial amount , b is the multiplicative rate of change in time period x.

Number of 3 hours period in 9 hours = 3

Therefore, x=3

Therefore, the amount of bacteria in the dish after 9 hours is given by :_

y=500(2)^3=500\times8=4000

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julia-pushkina [17]

Answer:

Height of tree 3 years ago: 24 inches

Height of tree now: 54 inches

54-24 = 30

The tree grew 30 inches in 3 years.

So on average it grew 10 INCHES PER YEAR.

Let me know if this helps!

3 0
2 years ago
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sweet-ann [11.9K]
B is the correct answer


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Given the general form of the sinusoidal function, y = AsinB(x - C) + D, match the following items.
Jet001 [13]

Answer:

\Delta y = A (Amplitude) (Correct answer: 1)

\omega = B (Angular frequency) (Correct answer: 2)

x_{o} = C (Phase shift) (Correct answer: 3)

y_{o} = D (Vertical shift) (Correct answer: 4)

\frac{2\pi}{\omega} = \frac{2\pi}{B} (Period) (Correct answer: 5)

Step-by-step explanation:

The general form of a sinusoidal function is represented by the following characteristics:

y = \Delta y \cdot \sin \omega\cdot (x- x_{o}) + y_{o} (1)

Where:

\Delta y - Amplitude.

\omega - Angular frequency.

x_{o} - Phase shift.

y_{o} - Vertical shift.

x - Independent variable.

y - Dependent variable.

In addition, we know that the period associated with the sinusoidal function (T) is:

T = \frac{2\pi}{\omega}

By direct comparison, we get the following conclusions:

\Delta y = A (Amplitude) (Correct answer: 1)

\omega = B (Angular frequency) (Correct answer: 2)

x_{o} = C (Phase shift) (Correct answer: 3)

y_{o} = D (Vertical shift) (Correct answer: 4)

\frac{2\pi}{\omega} = \frac{2\pi}{B} (Period) (Correct answer: 5)

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Answer:

See below

Step-by-step explanation:

Here we need to prove that ,

\sf\longrightarrow sin^2\theta + cos^2\theta = 1

Imagine a right angled triangle with one of its acute angle as \theta .

  • The side opposite to this angle will be perpendicular .
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\sf\longrightarrow sin\theta =\dfrac{p}{h} \\

\sf\longrightarrow cos\theta =\dfrac{b}{h}

And by Pythagoras theorem ,

\sf\longrightarrow h^2 = p^2+b^2 \dots (i)

Where the symbols have their usual meaning.

Now , taking LHS ,

\sf\longrightarrow sin^2\theta +cos^2\theta

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\sf\longrightarrow \bigg(\dfrac{p}{h}\bigg)^2+\bigg(\dfrac{b}{h}\bigg)^2\\

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Since LHS = RHS ,

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