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3 years ago

Choose the pair of numbers that is not a solution to the given equation.

Mathematics

1 answer:

balandron [24]3 years ago

3 0

Answer:

The pair (0,3) is not a solution to the equation

Step-by-step explanation:

This can be proved by simply replacing the x and y variables in the equation by the x and y values of the pair, and checking if the equation renders a true statement:

By replacing x and y with their values in the pair (0,3), that is x=0 and y=3, in the equation y = 5 - 2x we get:

3 = 5 - 2 (0)

3 = 5 - 0

3 = 5

which is NOT a true statement.

On the other hand, the other two pairs (2,1) and (1,3) render true statements:

1 = 5 - 2 (2)

1 = 5 - 4

1 = 1

and

3 = 5 - 2 (1)

3 = 5 - 2

3 = 3

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The value of y varies directly with x and y=3 when x=-6. Find y when x=1

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3 years ago

2. Consider the circle x² + y2 = 1, given in figure. Let OP makes an angle 30° with the x axis.

PolarNik [594]

The equation of the tangent line to the circle passing through the point P is; y = (1/√3)x ± 2/√3

<h3>How to find the equation of the tangent?</h3>

I) We are given the equation of the circle as;

x² + y² = 1

Since angle of inclination is 30°, then slope is;

m = tan 30 = 1/√3

Then equation of the tangent will be;

y = (1/√3)x + c

Put (√3)x + c into the given circle equation to get;

x² + ((1/√3)x + c)² = 1

x² + ¹/₃x² + (2/√3)cx + c² = 1

⁴/₃x² + (2/√3)x + (c² - 1) = 0

Since we need to find value of c for equation to become tangent, then the above quadratic equation must have real and equal roots.

Thus;

((2/√3)c)² - 4(⁴/₃)(c² - 1) = 0

⁴/₃c² - ¹⁶/₃(c² - 1) = 0

⁴/₃c² - ¹⁶/₃c² + ¹⁶/₃ = 0

4c² = ¹⁶/₃

c² = ⁴/₃

c = √⁴/₃

c = ±²/√3

Thus, equation of tangent is;

y = (1/√3)x ± 2/√3

II) Radius from the given equation is 1. Thus, we will use trigonometric ratio to find the x and y intercept;

x-intercept is at y = 0;

0 = (1/√3)x ± 2/√3

-(1/√3)x = ±2/√3

Intercept is positive. Thus;

x = (2/√3)/(1/√3)

x = 1

y - intercept is positive at x = 0;

y = (1/√3)0 ± 2/√3

y = 2/√3

Read more about Equation of tangent at; brainly.com/question/17040970

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1 year ago

Whats the ninth term of 25 20 15 10 5

Kaylis [27]

Given:

The sequence is 25, 20, 15, 10, 5.

To find:

The ninth term of the given sequence.

Solution:

We have,

25, 20, 15, 10, 5

It is an AP because the difference between two consecutive terms are same.

Here,

First term (a) = 25

Common difference (d) = 20-25

= -5

The nth terms of an AP is

$a_n=a+(n-1)d$

Where, a is the first term and d is the common difference.

Putting a=25, n=9 and d=-5 to get the 9th term.

$a_9=25+(9-1)(-5)$

$a_9=25+(8)(-5)$

$a_9=25-40$

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Therefore, the ninth term of the given sequence is -15.

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2 years ago

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lys-0071 [83]

In solving algebraic expressions, there is an order in which to solve it.

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3) apply multiplication and division from left to right of the equation.
4) apply addition and subtraction from left to right of the equation.

Remember this: PEMDAS for easier recall. (parenthesis, exponents, multiplication, division, addition, subtraction)

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Answer:

43.3cm

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