Please help almost late:(

Use any method to multiply (3a + 2b – c)(a – b + 2c).

umka21 [38]

Answer:

A)

3a2 – 2b2 – 2c2 – ab + 5ac + 5bc

$(3a + 2b - c)(a - b + 2c) \\ = (3 {a}^{2} - 3ab + 6ac + 2ab - 2 {b}^{2} + 6bc - ac + bc - 2 {c}^{2} ) \\ = 3 {a}^{2} - ab + 5ac - 2 {b}^{2} + 5bc - {2c}^{2} \\ = 3 {a}^{2} - 2 {b}^{2} - {2c}^{2} - ab + 5ac + 5bc$

4 0

3 years ago

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Twice a real number is 6 times more than half that number. Determine this<br> number

Jet001 [13]

Answer:

4

Step-by-step explanation:

Assign x for the number. Write an equation.

2x = 6+.5x (I'm guessing you means "6 more than half that number")

1.5x = 6 -->

x = 4

5 0

3 years ago

A certain company makes three grades (A, B, and C) of a particular electrical component. Historically, grade A components have a

IrinaK [193]

Answer:

following are the solution to this question:

Step-by-step explanation:

In part (a):

Phase 1: Identifies a reasonable confidence period with both the title or form and checks suitable conditions. one z-interval test, p, that true percentage of defective parts in such a lot of Clauses:

1. Unique component sampling

2. This survey size is enough, to the fact to conclude the composition of that percentage of a sample was roughly natural, which the amount for successes and the number of losses are either greater than 10 (or 5 or 15). Needs to check: A 200-component representative selection of a big batch was picked. Each has far more than 15 achievements or failures (16 and 184).

Phase 2: Mechanisms Correct Pick problems for Pink and Blue it Committee of a College. Similar products are part of the program of a College Board. It is prohibited for such resources to be used and distributed online or in a printed form far beyond the participation of the college in the package, which leads to intervals (0.0424, 0.1176).

Phase 3: Background analysis In just this study, we consider 95% of its computed value to have between 4.24% and 11.76% for both the real number of defective components within the batch.

In part (b):

Its standard deviation of 95 percent found in Part (a) allows a company to eliminate class A as its 2 percent faulty rate is not among the computed value within this interval. It period however does not enable the company to decide between levels B and C, since the two faulty rates (5% and 10%) were examined.

Scoring: In 4 components the question is rated. Section 1 comprises part (a) step 1; part (a) or step 2 comprises of the part (a), part (3), part (a), and part (4) (b). The part was marked as correct (E), partly right (P) (I).

4 0

3 years ago

The graph below is a portion of a complete graph. Choose the complete graph assuming it is an odd function.

WARRIOR [948]

Answer: I’d say D

Step-by-step explanation:

a guess but at least its educated

GOOD LUCK

7 0

2 years ago

D. Evaluate each of the following. (5 points)

Harrizon [31]

Problem 1

f(x) = x + 1/x

f(1) = 1 + 1/1

f(1) = 1 + 1

f(1) = 2

Answer: 2

============================================

Problem 2

(f o f)(1) = f( f(1) )

(f o f)(1) = f( 2 )

(f o f)(1) = 2 + 1/2

(f o f)(1) = 4/2 + 1/2

(f o f)(1) = 5/2

Answer: 5/2

============================================

Problem 3

(f o f o f)(1) = f( f(f(1)) )

(f o f o f)(1) = f( (f o f)(1) )

(f o f o f)(1) = f( 5/2 )

(f o f o f)(1) = 5/2 + 1/(5/2)

(f o f o f)(1) = 5/2 + 2/5

(f o f o f)(1) = 25/10 + 4/10

(f o f o f)(1) = 29/10

Answer: 29/10

============================================

Problem 4

(f o f o f o f)(1) = f( f(f(f(1)) )

(f o f o f o f)(1) = f( (f o f o f)(1) )

(f o f o f o f)(1) = f( 29/10 )

(f o f o f o f)(1) = 29/10 + 1/(29/10)

(f o f o f o f)(1) = 29/10 + 10/29

(f o f o f o f)(1) = 841/290 + 100/290

(f o f o f o f)(1) = 941/290

Answer: 941/290

============================================

Problem 5

(f o f o f o f o f)(1) = f( f(f(f(f(1)))) )

(f o f o f o f o f)(1) = f( (f o f o f o f)(1) )

(f o f o f o f o f)(1) = f( 941/290 )

(f o f o f o f o f)(1) = 941/290 + 1/(941/290)

(f o f o f o f o f)(1) = 941/290 + 290/941

(f o f o f o f o f)(1) = 885481/272890 + 84100/272890

(f o f o f o f o f)(1) = 969581/272890

Answer: 969581/272890

4 0

3 years ago

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