Answer:
Explanation:
mass, m = 1 kg
Position (2, 3 ) m
height, h = 2 m
acceleration due to gravity, g = 9.8 m/s^2
Here, no force is acting in horizontal direction, the force of gravity is acting in vertical direction, so the work done by the gravitational force is to be calculated.
Force mass x acceleration due to gravity
F = 1 x 9.8 = 9.8 N
Work = force x displacement x CosФ
Where, Ф be the angle between force vector and the displacement vector.
Here the value of Ф is 180° as the force acting vertically downward and the displacement is upward
So, W = 9.8 x 2 x Cos 180°
W = - 19.6 J
Thus, option (A) is correct.
The sun is the centre of our solar system
Let's cut through the weeds and the trash
and get down to the real situation:
A stone is tossed straight up at 5.89 m/s .
Ignore air resistance.
Gravity slows down the speed of any rising object by 9.8 m/s every second.
So the stone (aka Billy-Bob-Joe) continues to rise for
(5.89 m/s / 9.8 m/s²) = 0.6 seconds.
At that timer, he has run out of upward gas. He is at the top
of his rise, he stops rising, and begins to fall.
His average speed on the way up is (1/2) (5.89 + 0) = 2.945 m/s .
Moving for 0.6 seconds at an average speed of 2.945 m/s,
he topped out at
(2.945 m/s) (0.6 s) = 1.767 meters above the trampoline.
With no other forces other than gravity acting on him, it takes him
the same time to come down from the peak as it took to rise to it.
(0.6 sec up) + (0.6 sec down) = 1.2 seconds until he hits rubber again.
Answer:
The value is ![\lambda = 1.329 *10^{-9} \ m](https://tex.z-dn.net/?f=%5Clambda%20%20%20%3D%201.329%20%2A10%5E%7B-9%7D%20%5C%20%20m)
Explanation:
From the question we are told that
The orbital radius is ![r = 0.846nm = 0.846 *10^{-9} \ m](https://tex.z-dn.net/?f=r%20%3D%20%200.846nm%20%3D%20%200.846%20%2A10%5E%7B-9%7D%20%5C%20m)
Generally the de Broglie wavelength is mathematically represented as
![\lambda = \frac{2 * \pi r}{4}](https://tex.z-dn.net/?f=%5Clambda%20%20%3D%20%20%5Cfrac%7B2%20%2A%20%20%5Cpi%20%20r%7D%7B4%7D)
substituting values
![\lambda = \frac{ 2 * 3.142 * 0.846 *10^{-9}}{4}](https://tex.z-dn.net/?f=%5Clambda%20%20%3D%20%20%5Cfrac%7B%202%20%2A%203.142%20%20%2A%20%200.846%20%2A10%5E%7B-9%7D%7D%7B4%7D)
![\lambda = 1.329 *10^{-9} \ m](https://tex.z-dn.net/?f=%5Clambda%20%20%20%3D%201.329%20%2A10%5E%7B-9%7D%20%5C%20%20m)