Answer:
Which means that the flux through each loop of the second coil is half as much as flux through each loop of first coil.
Explanation:
The flux through each loop of the first coil due to current in the second coil is,
The number of loops in the first coil is
no. of loops = 2N
Total flux passing through the first coil is
The flux through each loop of the second coil due to current in the first coil is,
The number of loops in the second coil is
no. of loops = N
Total flux passing through the second coil is
Comparing both
Which means that the flux through each loop of the second coil is half as much as flux through each loop of first coil.
Velocity vs. time graph shows the acceleration as a slope whereas displacement vs. time graph shows the velocity as a slope. So, the given statement is false.
Answer: Option B
<u>Explanation:</u>
To understand the acceleration graphically, consider the x axis of the graph as the run and the y axis as the velocity rise. Now, as we all know that,
We can estimate this through the graph. let's draw the motion of an object with time if it's velocity is changing in every second by 4 m/s. Now if we draw this on graph, we will see that there is a slope between the two corresponding values of time and velocity. This slope defines the acceleration for the object with time.
Now, in the same way, if we draw a distance and time graph respective to the y and x axis; we'll get a slope which defines the velocity of the object i.e. change in distance with time.
Hence, with a velocity vs time graph, we get the slope for acceleration whereas with the distance and time graph, we get the slope for velocity. So both the cases, we see there is no velocity slope on an acceleration and time graph. Hence the statement is false.
The work done on the given gas in one cycle is -405.3 kJ.
The given parameters;
- <em>initial pressure of the gas, P₁ = 2 atm</em>
- <em>final pressure of the gas, P₂ = 6 atm</em>
- <em>initial volume of the gas, V₁ = 1 m³</em>
- <em>final volume of the gas, V₂ = 3 m³</em>
Convert the pressure to Pascal (N/m²);
1 atm = 101325
The work done in one cycle is the area of the triangle and it is calculated as follows
the net work done on the gas = - 405.3 kJ
Thus, the work done on the given gas in one cycle is -405.3 kJ.
Learn more about work done in compressing gas here: brainly.com/question/19579139
Answer:
The answer is 0.2 .
Explanation:
We can calculate the acceleration since we know that acceleration is change in velocity over time or:
a =Δv/t
where a = acceleration, Δv = change in velocity, t = time.
We know that Δv = v2 - v1 where, v2 = 10 m/s and v1 = 6 m/s
Therefore,
a =