B. Reversing the current direction will cause the force deflecting the
wire to be perpendicular to the magnetic field but in the opposite
direction.
An object at rest stays at rest and an object in motion<span> stays in </span>motion <span>with the same speed and in the same direction unless acted upon by an unbalanced force.
I hope this helps you </span>
Answer:
54%
Explanation:
So, we have that the "magnitude of its displacement from equilibrium is greater than (0.66)A—''. Thus, the first step to take in answering this question is to write out the equation showing the displacement in simple harmonic motion which is = A cos w×t.
Therefore, we will have two instances t the displacement that is to say at a point 2π/w - a2 and the second point at a = a2.
Let us say that 2π/w = A, then, we have that a = A cos ^-1 (0.66)/2π. Also, we have that a2 = A/2 - A cos^- (0.66) / 2π.
The next thing to do is to calculate or determine the total length of of the required time. Thus, the total length is given as:
2a1 + ( A - 2a2) = 2A{ cos^-1 (0.66)}/ π.
Therefore, the total percentage of the period does the mass lie in these regions = 100 × {2a1 + ( A - 2a2) }/A = 2 { cos^-1 (0.66)}/ π × 100 = 54%.
Thus, the total percentage of the period does the mass lie in these regions = 54%.
Answer:
Explanation:
An object is thrown up from a height of 520m
h_o = 520m
Initial velocity of thrown is 18m/s
u = 18m/s
What is the position of the object after 3seconds
t = 3s
Acceleration due to gravity
g = 9.81 m/s²
Let calculated the height the object will reached when thrown from the top.
Using equation of motion
h = ut + ½gt²
Since the body is thrown upward, it is acting against gravity then, gravity will be negative
Then,
h = ut — ½gt²
h = 18 × 3 — ½ × 9.81 × 3²
h = 54 — 44.145
h = 9.855 m
So, the body is above the top of the building at a distance of 9.855m
So, the total distance from the bottom is
Position = h + h_o
x = 9.855 + 520
x = 529.855m
x ≈ 530m,
The position of objects after 3seconds is 520m
Answer:
When the average kinetic energy of its particles increases, the object's thermal energy increases. Therefore, the thermal energy of an object increases as its temperature increases.
