Polarized light waves are those that have only one plane of vibration. Polarization is the process by which non-polarized light is converted into polarised light. There are numerous ways to polarise light.
A characteristic of transverse waves called polarisation identifies the geometric angle of the oscillations. A transverse wave's oscillation direction is perpendicular to the wave's motion direction.
given
Only 72.0% of the light's intensity makes it through the sheet and hits another sheet of polarising material. The second sheet lets no light flow through it.
Given that no light passes through the second sheet because both sheets are crossed, the angle the transmission axis of the second sheet makes with the vertical is
θ₂ = θ₁ + 90°
= 31.94° + 90°
= 1 21.94°
for the first sheet and
Icos²θ₁ = I
I/I₀ = 0.72
θ₁ = cos⁻¹√(0.72)
= 31.94°
for the second sheet, respectively. This is because the malus law states that I = Iocos²θ₁ for the first sheet.
To know more about light that is polarized, click on the link below:
brainly.com/question/3092611
#SPJ4
The electromagnetic waves do not need any medium to travel as they are not mechanical in nature. They propagate in the form of electric and magnetic energy having a perpendicular vector of its velocity wave
three types
The three types of thermal expansions are Linear expansion , Superficial expansion and Cubical expansion.
Both travel in waves caused by vibrations. Both can be reflected refracted, and diffracted.
Explanation:
It is given that,
Mass of the box, m = 10 kg
Force with which the box is pulled, F = 50 N
It is moved a distance of 4 m
Force of friction acting on the box, f = 20 N
We need to find the initial kinetic energy the box have. It is clear that the box is at rest initially. As there is no motion in the box at that time. The formula for the kinetic energy of the box is given by :
![E_k=\dfrac{1}{2}mv^2](https://tex.z-dn.net/?f=E_k%3D%5Cdfrac%7B1%7D%7B2%7Dmv%5E2)
As v = 0
![E_k=0](https://tex.z-dn.net/?f=E_k%3D0)
So, the initial kinetic energy of the box is 0. Hence, this is the required solution.