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Fed [463]
3 years ago
8

A total of 330 children and adults attended a school play. There were 21 times as many children in attendance as there were adul

ts.
This situation is modeled by the given system of equations, where a represents the number of adults and c represents the number of children.

c = 21a

a + c = 330

How many children attended the play?
Mathematics
2 answers:
Pani-rosa [81]3 years ago
6 0

Answer:

15

Step-by-step explanation:

vovangra [49]3 years ago
5 0

Answer:

315 children

Step-by-step explanation:

a + 21a = 330 {substituted 21a, in for c, into second equation}

22a = 330 {combined like terms}

a = 15 {divided each side by 22}

15 adults attended

c = 21a {first original equation}

c = 21(15) {substituted 15,

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7. Bill and Steve both owe their mother money. Bill owes his mother $300 and plans
Free_Kalibri [48]

Answer:

5 weeks

$175

Step-by-step explanation:

Bill owes his mother $300 and plans to pay her $25 every week.

Therefore, after w weeks he has to give her mother more C = 300 - 25w, amount of money.

Steve owes his mother $550 and plans to pay her  $75 every week.

Therefore, after w weeks he has to give her mother more C = 550 - 75w, amount of money.

If after w weeks they both will owe their mother the same amount of money, then  

300 - 25w = 550 - 75w

⇒ w = 5 weeks. (Answer)

Now, the amount of money will be $(300 - 25 × 5) = $175. (Answer)

4 0
3 years ago
Over the last 3 months, Janet exercised a total of 101 hours. She exercised 4 hours more during the second month than the first
olganol [36]

In 1st month let she exercised h hours

in second month she exercised h+4 hours

in third month she exercised h+4-3=h+1 hours

Now

  • h+h+4+h+1=101
  • 3h+5=101
  • 3h=96
  • h=32hours
3 0
2 years ago
Read 2 more answers
WILLL GIVE BRAINLIEST + 50 POINTS FOR HELP!!!!<br><br><br>PLZZZZZZ IM TIMED
andrew-mc [135]
First. y=2x
second d is correct
third is a
7 0
3 years ago
Read 2 more answers
For the polynomial function ƒ(x) = −x6 + 3x4 + 4x2, find the zeros. Then determine the multiplicity at each zero and state wheth
murzikaleks [220]

There is a multiple zero at 0 (which means that it touches there), and there are single zeros at -2 and 2 (which means that they cross). There is also 2 imaginary zeros at i and -i.


You can find this by factoring. Start by pulling out the greatest common factor, which in this case is -x^2.


-x^6 + 3x^4 + 4x^2

-x^2(x^4 - 3x^2 - 4)


Now we can factor the inside of the parenthesis. You do this by finding factors of the last number that add up to the middle number.


-x^2(x^4 - 3x^2 - 4)

-x^2(x^2 - 4)(x^2 + 1)


Now we can use the factors of two perfect squares rule to factor the middle parenthesis.


-x^2(x^2 - 4)(x^2 + 1)

-x^2(x - 2)(x + 2)(x^2 + 1)


We would also want to split the term in the front.


-x^2(x - 2)(x + 2)(x^2 + 1)

(x)(-x)(x - 2)(x + 2)(x^2 + 1)


Now we would set each portion equal to 0 and solve.


First root

x = 0 ---> no work needed


Second root

-x = 0 ---> divide by -1

x = 0


Third root

x - 2 = 0

x = 2


Forth root

x + 2 = 0

x = -2


Fifth and Sixth roots

x^2 + 1 = 0

x^2 = -1

x = +/- \sqrt{-1}

x = +/- i

7 0
3 years ago
If John drove 210 miles in 3 hours, how far will he have<br> driven in 4.5 hours?
VashaNatasha [74]

Answer:

3hours and 15 mins

Step-by-step explanation:

210 divied by 3=70

70=per hour

4 hours=280

70 divied by 2= 35

.5=35

280+35=315

315 miles in 4.5 hours

3 0
3 years ago
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