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Savatey [412]
3 years ago
13

What are the concentrations of h3o+ and oh− in tomatoes that have a ph of 4.10?

Chemistry
1 answer:
IRINA_888 [86]3 years ago
5 0

Answer : The concentration of H_3O^+ and OH^- are 7.94\times 10^{-5} and 1.258\times 10^{-10} respectively.

Solution : Given,

pH = 4.10

pH : pH is defined as the negative logarithm of hydronium ion concentration.

Formula used : pH=-log[H_3O^+]

First we have to calculate the hydronium ion concentration by using pH formula.

4.10=-log[H_3O^+]

[H_3O^+]=antilog(-4.10)

[H_3O^+]=7.94\times 10^{-5}

Now we have to calculate the pOH.

As we know, pH+pOH=14

4.10+pOH=14

pOH=9.9

Now we have to calculate the hydroxide ion concentration.

pOH=-log[OH^-]

9.9=-log[OH^-]

[OH^-]=antilog(-9.9)

[OH^-]=1.258\times 10^{-10}

Therefore, the concentration of H_3O^+ and OH^- are 7.94\times 10^{-5} and 1.258\times 10^{-10} respectively.

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If you combine 230.0 mL of water at 25.00 ∘ C and 140.0 mL of water at 95.00 ∘ C, what is the final temperature of the mixture?
IgorLugansk [536]

<u>Answer:</u> The final temperature of the mixture is 51.49°C

<u>Explanation:</u>

When two samples of water are mixed, the heat released by the water at high temperature will be equal to the amount of heat absorbed by water at low temperature

Heat_{\text{absorbed}}=Heat_{\text{released}}

The equation used to calculate heat released or absorbed follows:

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

m_1\times c\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]       ......(1)

where,

q = heat absorbed or released

m_1 = mass of water at high temperature = 140 g     (Density of water = 1.00 g/mL)

m_2 = mass of water at low temperature = 230 g

T_{final} = final temperature = ?°C

T_1 = initial temperature of water at high temperature = 95.00°C

T_2 = initial temperature of water at low temperature = 25.00°C

c = specific heat of water= 4.186 J/g°C

Putting values in equation 1, we get:

140\times 4.186\times (T_{final}-95)=-[230\times 4.186\times (T_{final}-25)]

T_{final}=51.49^oC

Hence, the final temperature of the mixture is 51.49°C

5 0
4 years ago
Hey guys. Sorry for all the questions. But I’m checking my answers for a Science test. Here are my questions.
morpeh [17]

Answer:

1. c 2. b that's what i think i learned this in middle school i dont completely remember

5 0
3 years ago
calculate the density of a rectangular solid, which has a mass of 25.71g. It is 2.30cm long, 4.01cm wide, and 1.82cm high
LUCKY_DIMON [66]
Volume of a rectangular block= 2.30x4.01x1.82=16.78cm3
Mass of the rectangular block= 25.71 g 
Density of the block will be = 25.71/16.78=1.53 g/cm3
So the 
ANSWER IS 1.53 g/cm3 density
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nasty-shy [4]
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