1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kramer
3 years ago
14

g The reaction C(s) + CO2(g) → 2CO(g) is spontaneous only at temperatures in excess of 1100 K. We can conclude that a. ΔG° is ne

gative for all temperatures. b. ΔH° is negative and ΔS° is negative. c. ΔH° is positive and ΔS° is positive. d. ΔH° is negative and ΔS° is positive. e. ΔH° is positive and ΔS° is negative.
Chemistry
1 answer:
mel-nik [20]3 years ago
7 0

Answer:

c. ΔH° is positive and ΔS° is positive.

Explanation:

Hello,

In this case, as the Gibbs free energy for a reaction is defined in terms of the change in the enthalpy and entropy as shown below:

\Delta G=\Delta H-T\Delta S

Thus, as the reaction becomes spontaneous (ΔG°<0) at temperatures above 1100K (high temperatures), it necessary that c. ΔH° is positive and ΔS° is positive as the entropy will drive the spontaneousness as it becomes smaller than TΔS°.

Best regards.

You might be interested in
How do atoms form a new compound? A: By sharing electrons with each other B: By losing electrons to each other C: By gaining ele
scoundrel [369]
By sharing electrons with one another
8 0
3 years ago
How will the following changes affect the mole fraction of chlorine gas, χcl2, in the equilibrium mixture.?
sammy [17]
If the reaction is represented by:
PCl₃ + Cl₂ <-> PCl₅ (exothermic)

the mole fraction of chlorine in the equilibrium mixture will change according to the following:
Decrease the volume: decrease
Increase the temperature: increase
Increase the volume: increase
Decrease the temperature: decrease
4 0
3 years ago
A salt lover decided to flavor her meal by adding 2.50 moles of sodium chloride,
FromTheMoon [43]

Answer: C, 146

Explanation:

NaCl has a molar mass of 58.44 g/mol.

To change moles to g, we do:

2.50 moles × 58.44 g/mol = 146.1 g, so C

4 0
2 years ago
Why would hand sanitizers not be as effective as detergents to clean your
deff fn [24]

Answer:

While both handwashing and hand sanitizing are good hygiene practices, each has its ... The difference between soaps and detergents lies in their ingredients and how they are made. ... Before handling clean equipment and serving utensils;; When changing tasks and switching ... Do not wash or rub it off on your clothes.

Explanation:

4 0
3 years ago
Find the mass of 4.5 moles of H3PO4
Contact [7]

Hey there!

H₃PO₄

Find molar mass.

H: 3 x 1.008 = 3.024

P: 1 x 30.97 = 30.97

O: 4 x 16 = 64

---------------------------------

                  97.994 grams

The mass of 1 mole of H₃PO₄ is 97.994 grams.

We have 4.5 moles.

97.994 x 4.5 = 440

The mass of 4.5 moles of H₃PO₄ is 440 grams.

Hope this helps!

6 0
3 years ago
Other questions:
  • If a glass bottle breaks into thousands of tiny pieces, what type of change occurs? A. physical only B. chemical only C. physica
    5·2 answers
  • How many grams of sodium benzoate, C H CO Na, have to be added to 1.50 L of a 0.0200 M solution of benzoic acid, C H CO H, to ma
    5·1 answer
  • If an isotope decay by process of beta emission
    8·1 answer
  • ASAP can someone help me think of a short title for testing water pH. Thank you !!!! :
    10·2 answers
  • A reaction proceeds with 2.72 moles of magnesium chlorate and 3.14 moles of sodium hydroxide. This is the equation of the reacti
    13·2 answers
  • What forces makes a fan stop spinning?
    9·2 answers
  • Please help I will mark Brainly
    10·1 answer
  • Determine the number of moles in 4.00x10^2 g of cesium iodide
    9·1 answer
  • Write a balanced half-reaction for the oxidation of manganese ion (mn2 ) to solid manganese dioxide (mno2) in acidic aqueous sol
    9·1 answer
  • Use Appendix C to choose the solution with the higher pH:0.1MSn{NO₃)₂ or 0.1MCoNO₃)₂
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!