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jasenka [17]
3 years ago
12

If an object has more positive charges than negative charges, the object has an overall?

Chemistry
1 answer:
djyliett [7]3 years ago
7 0
The object has an overall positive charge.
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Is Kl covalent or ionic?
kotegsom [21]
I believe that the answer is ionic
3 0
3 years ago
A 13-gram rubber stopper is attached to a 0.93-meter
makkiz [27]
<h3>Answer:</h3>

The centripetal acceleration is 26.38 m/s²

<h3>Explanation:</h3>

We are given;

  • Mass of rubber stopper = 13 g
  • Length of the string(radius) = 0.93 m
  • Time for one revolution = 1.18 seconds

We are required to calculate the centripetal acceleration.

To get the centripetal acceleration is given by the formula;

Centripetal acc = V²/r

Where, V is the velocity and r is the radius.

Since time for 1 revolution is 1.18 seconds,

Then, V = 2πr/t, taking π to be 3.142 ( 1 revolution = 2πr)

Therefore;

Velocity = (2 × 3.142 × 0.93 m) ÷ 1.18 sec

             = 4.953 m/s

Thus;

Centripetal acceleration = (4.953 m/s)² ÷ 0.93 m

                                        = 26.38 m/s²

Hence, the centripetal acceleration is 26.38 m/s²

6 0
3 years ago
Plz help for chemistry quiz I’ll mark brainliest
zvonat [6]

Answer: All of these answers are sorrect

ExplanationA scientist does all of these things while operforming a experiment

4 0
3 years ago
The length of the school's gymnasium is 30 meters long. How many centimeters long is the school's gymnasium​
aleksley [76]

Answer:

The answer to your question is: 3000 cm

Explanation:

30 meters long to cm

We can use a rule of three to solve it

We know that              1 meter ------------------  100 cm

                                  30 meters ----------------    x

                               x = 30(100)/1 = 3000 cm

5 0
3 years ago
Read 2 more answers
How many atoms of iodine are in 12.75g of CaI2? Hint. How many Iodines are there in one CaI2 particle?
xenn [34]

Answer:

5.225x10^{22}atoms\ I

Explanation:

Hello!

In this case, since 12.75 g of calcium iodide has the following number of moles (molar mass = 293.89 g/mol):

n_{CaI_2}=12.75gCaI_2*\frac{1molCaI_2}{293.89gCaI_2}=0.0434molCaI_2

In such a way, since 1 mole of calcium iodide contains 2 moles of atoms of iodine, and one mole of atoms of iodine contains 6.022x10²³ atoms (Avogadro's number), we compute the resulting atoms as shown below:

atoms\ I=0.0434molCaI_2*\frac{2molI}{1molCaI_2} *\frac{6.022x10^{23}atoms\ I}{1molI} \\\\atoms\ I = 5.225x10^{22}atoms\ I

Best regards!

4 0
3 years ago
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