<span>To answer this question, the equation that we will be using is:
y = A cos bx + c
where A = amplitude, b = 2 pi/Period, Period = 12 hrs, c = midline,
x = t and y = f(t)
A = 1/2 (Xmax - Xmin)
12 - 2 / 2 = 10/2 = 5
b = 2 pi / 12 = pi/6
c = 1/2 (Xmax + Xmin)
12+2/2 = 7
answer: f(t) = 5 cos pi/6 t + 7 </span>
Answer: 225N to the right
Explanation:
The pedaling force is to the right and of 325N.
The air resistance is to the opposite side (in this case to the left) of 100N.
To find Net force of an object with two opposite forces acting on them then we have to subtract the smaller force from the bigger force and but the direction of the bigger force, so
325N-100N=225N
The greater force is towards the right proving the direction of the Net force is to the right.
Therefore the Net force is 225N to the right.
Please mark me brainliest.
I don't like any of those choices. But if you absolutely have to pick your answer
from this list, then it has to be 'D'.
The ocean is an enormous storage vessel for heat. It gets heat from the air in
the Summer ... which somewhat cools places near the coast ... and it releases
heat into the air during the Winter ... which warms places near the coast.
So I guess it's true that ocean surfaces change temperature more slowly than
land surfaces do, and they influence the land nearby in the process. But this
ignores the reason for the slow changes in ocean surface temperature. It's a
lot like saying that the loud noise produced by a race car is the result of the
car's ability to appear in a far different location after a short time.
First of all you need to have in mind the following data:
<span>Mass of Mars: 6.43 x 10^23 kg
Radius of Mars: 3.40 x 10^6 m
Formulas: F = G(m1)(m2)/(r^2), m1 = F(r^2)/G(m2), m2 = F(r^2)/G(m1), F = ma
G = 6.67 x 10^-11
</span><span> We can say that the first and second objects with mass can be called as following:
m1= centre of Mars
m2 = will be the ball.
</span>The distance between them = the radious of mars.
