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7nadin3 [17]
3 years ago
12

Metal sphere A has a charge of − Q . −Q. An identical metal sphere B has a charge of + 2 Q . +2Q. The magnitude of the electric

force on sphere B due to sphere A is F . F. The magnitude of the electric force on sphere A due to sphere B must be:
Physics
1 answer:
Goshia [24]3 years ago
3 0

Complete Question:

Metal sphere A has a charge of − Q . −Q. An identical metal sphere B has a charge of + 2 Q . +2Q. The magnitude of the electric force on sphere B due to sphere A is F . F. The magnitude of the electric force on sphere A due to sphere B must be:

A. 2F

B. F/4

C. F/2

D. F

E. 4F

Answer:

D.

Explanation:

If both spheres can be treated as point charges, they must obey the Coulomb's law, that can be written as follows (in magnitude):

F =\frac{kQ*2Q}{r^{2} }

As it can be seen, this force is proportional to the product of the charges, so it must be the same for both charges.

As this force obeys also the Newton's 3rd Law, we conclude that the magnitude of the electric force on sphere A due to sphere B, must be equal to the the magnitude of the force on the sphere B due to the sphere A, i.e., just F.

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Answer:

9 meters

Explanation:

Given:

Mass of Avi is, m=40\ kg

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Compression in the spring is, x=20\ cm=0.20\ m

Let the maximum height reached be 'h' m.

Now, as the spring is compressed, there is elastic potential energy stored in the spring. This elastic potential energy is transferred to Avi in the form of gravitational potential energy.

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Decrease in elastic potential energy is given as:

EPE=\frac{1}{2}kx^2\\EPE=\frac{1}{2}\times 176400\times (0.20)^2\\EPE=88200\times 0.04=3528\ J

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Now, increase in gravitational potential energy is equal decrease in elastic potential energy. Therefore,

392h=3528\\\\h=\frac{3528}{392}\\\\h=9\ m

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6 0
3 years ago
A wire with resistance R is connected to the terminals of a 6.0 V battery. What is the potential difference between the ends of
Bas_tet [7]

Answer:

Potential difference = 6.0 V

I for 1.0Ω = 6 A

I for 2.0Ω = 3 A

I for 3.0Ω = 2 A

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I = ΔV/R

When R = 1.0, I =6/1 = 6 amperes

When R = 2.0, I = 6/2 = 3 amperes

When R = 3.0, I = 6/3 = 2 amperes

<em>The potential difference is 6.0 V and the current is 6, 3, and 2 amperes for a resistance of 1.0, 2.0 and 3.0Ω respectively.</em>

7 0
2 years ago
How would the seasons change if the earth were tilted at 90 degrees instead of 23.5?
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3 years ago
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7 0
2 years ago
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Angelina_Jolie [31]

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