Answer:
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Step-by-step explanation:
Ms.Abigail just sent a email to you saying you failed or you had to do this again cus you aint do it this is the Unit 4 test aint it ;-;
Answer:
Step-by-step explanation:
1) a variable term contains a variable. If x is a variable
5x is an example of a variable therm
2) a constant therm is not a variable
3 is an example
3) for example when a number multiply a sum or a difference between a constant and a variable
Example:
2(x-3) = 5(x+4)
4) one solution: only if x is equal to 0 the equation is true
5) no solution: the equation can’t be true for ever value of the variable
6) infinite solutions: the equation is ever true for every value of the variable
We know that
for
y=a(x-h)^2+k
vertex is (h,k)
given vertex is (3,5)
y=a(x-3)^2+5
we are also given
(5,-3)
x=5 and y=-3 is a possible solution
-3=a(5-3)^2+5
-3=a(2)^2+5
minus 5 both sides
-8=a(4)
-8=4a
divide by 4 both sides
-2=a
the equation is
We label each equation
3x + 4y = 5 (1)
2x – 3y = 9 (2)
We now want to get rid of one of the variables (x or y). Lets get rid of x:
We need (1) and (2) to have the same number of x's so we multiple (1) by 2 and (2) by 3 so they both have 6 x's
6x + 8y = 10 (1)*2
6x - 9y = 27 (2)*3
Now to get rid of the x's we take one of the equations from the other. It is easier to do (2)*3 -(1)*2
6x - 9y = 27 (2)*3
6x + 8y = 10 (1)*2
-17y = 17
If we devide this equation by -17 we get
y = -1
We can plug this value of y into (1) to get
3x -4 = 5
add 4 to both sides of the equation
3x = 9
Divide by 3
x = 3
Now to check put x and y into (2)
6 - (-3) = 9
As this is true, we have the solution
x = 3, y = -1