Answer:
the vertical acceleration is 9.8 m/s,
downward and no horizontal acceleration..
Answer:
Explanation:
Given:
dI/dt = 6.21 A/s
n = N/l
= 100 turns/cm
= 100 turns/cm × 100 cm/1 m
Radius, r = 14.7 cm
= 0.147 m
Inductance, L = uo × n^2 × A × l
L/l = 4pi × 10^-7 × (100 × 100)^2 × pi × 0.147^2
= 8.53 H
Emf, E = L × dI/dt
E/l = L/l × dI/dt
= 8.53 × 6.21
= 52.98 V/m
=
Answer:
oxygen gains two electron to attain electron configuration like neon. Oe-²
Explanation:
Explanation:
Given that,
The force exerted by the stick on the puck is 975 N
The stick is in contact with the puck for 0.0049 s
Initial speed of the puck, u = 0 (at rest)
(a) We need to find the impulse imparted by the stick to the puck.
Impulse = Force × time
J = 4.7775 kg-m/s
(b) Mass of the puck, m = 1.76 kg
We need to find the speed of the puck just after it leaves the hockey stick.
Let the speed be v.
As impulse is equal to the change in momentum.

So, when the puck leaves the hockey stick its speed is 2.86 m/s.
The mass is 13.766 kilograms