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sattari [20]
3 years ago
8

Calculate the number of joules released when 72.5 grams of water at 95.0 degrees Celsius cools to a final temperature of 28.0 de

grees Celsius.
Chemistry
1 answer:
Airida [17]3 years ago
7 0
Water's specific heat capacity is 4200 J/Kg°C
95-28=67
72.5grams in kg is 0.0725kg
Energy = 67×0.0725×4200
Energy = 20,401.5 J or 20.4015 kJ
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3 years ago
Read 2 more answers
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