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boyakko [2]
3 years ago
15

9 ( x + 3 ) - (2x + 5)

Mathematics
1 answer:
Ivahew [28]3 years ago
4 0

Answer:

7x+22

Step-by-step explanation:

expand: 9x+27-2x-5

put together:<u><em> 7x+22</em></u>

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If you do not know it plz do not answer
kumpel [21]

385 miles

Step-by-step explanation:

440/16 = x/14

16x = 440 × 14

16x = 6,160

x = 6,160/16

x = 385 miles

8 0
3 years ago
Dilate the the triangle, scale factor = 3 (positive 3, ignore the
HACTEHA [7]

Answer:

The rule of dilation is P'(x,y) = 3\cdot P(x,y).

The vertices of the dilated triangle are A'(x,y) = (-21, -18), B'(x,y) = (-15,-10) and C'(x,y) = (-3,-15), respectively.

Step-by-step explanation:

From Linear Algebra, we define the dilation by the following definition:

P'(x,y) = O(x,y) + k\cdot[P(x,y)-O(x,y)] (1)

Where:

O(x,y) - Center of dilation, dimensionless.

k - Scale factor, dimensionless.

P(x,y) - Original point, dimensionless.

P'(x,y) - Dilated point, dimensionless.

If we know that O(x,y) = (0,0), k = 3, A(x,y) = (-7,-6), B(x,y) = (-5,-2) and C(x,y) =(-1,-5), then dilated points of triangle ABC are, respectively:

A'(x,y) = O(x,y) + k\cdot [A(x,y)-O(x,y)] (2)

A'(x,y) = (0,0) + 3\cdot [(-7,-6)-(0,0)]

A'(x,y) = (-21, -18)

B'(x,y) = O(x,y) + k\cdot [B(x,y)-O(x,y)] (3)

B'(x,y) = (0,0) + 3\cdot [(-5,-2)-(0,0)]

B'(x,y) = (-15,-10)

C'(x,y) = O(x,y) + k\cdot [C(x,y)-O(x,y)] (4)

C'(x,y) = (0,0) +3\cdot [(-1,-5)-(0,0)]

C'(x,y) = (-3,-15)

The rule of dilation is:

P'(x,y) = 3\cdot P(x,y) (5)

The vertices of the dilated triangle are A'(x,y) = (-21, -18), B'(x,y) = (-15,-10) and C'(x,y) = (-3,-15), respectively.

7 0
3 years ago
Which equation has an a-value of 1, a b value of -3 and a c- value of -5?
Vitek1552 [10]
If the answers are in the standard form of a line then it would be -x + (-3x) = -5y. This is because the standard form of a line is written as Ax + Bx = Cy
9 0
3 years ago
Label the percent bar below with the appropriate estimations.
Lapatulllka [165]

100÷4=25

25×4=100

so the answers for the a,b,and c is 25%

3 0
4 years ago
What is the solution of 3+ X-2/x-3 less than or equal to 4
Archy [21]

Answer:

Step-by-step explanation:

3+3+\frac{x-2}{x-3} \leq 4\\\\\frac{x-2}{x-3} \leq 4-3\\\frac{x-3+1}{x-3} \leq 1\\1+\frac{1}{x-3} \leq 1\\\frac{1}{x-3} \leq 0\\x-3 \leq 0\\x\leq 3

5 0
3 years ago
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