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Andre45 [30]
3 years ago
13

What is the lateral area of the prism? Assume the figure is resting on its base.

Mathematics
2 answers:
dolphi86 [110]3 years ago
8 0
Check the picture below.

the lateral area, namely the area of the sides, as you see in the picture, is really just the area of 6 rectangles.

front and back, two rectangles of 5x25,

left and right, two rectangles of 2x25.

simply get the area of each and sum them up, that's the lateral area of the prism.

\bf \stackrel{\textit{front and back}}{2(5\cdot 25)}~~~~+~~~~\stackrel{\textit{left and right}}{2(2\cdot 25)}

Liono4ka [1.6K]3 years ago
8 0
Your answer is 250 l*h*w
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Answer:

Step-by-step explanation:

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The point nearest to the origin on a line is at (4, -4). Find the standard form of the equation of the line.
Scrat [10]

Just did a specific one of these; let's do the general case.


The point nearest the origin is (a,b).


The line from the origin through the point is


bx - ay = 0


The line we seek is perpendicular to this one. We swap the coefficients on x and y, negating one, to get the perpendicular family of lines. We set the constant by plugging in the point (a,b):


ax + by = a^2 + b^2


ax + by -( a^2 + b^2) = 0


That's standard form; let's plug in the numbers:


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3 years ago
Urgent!! Will mark brainliest!!
anastassius [24]

Answer:

1) tanФ = 0.8392 ⇒ 2nd answer

2) cosФ = 20/29 ⇒ 3rd answer

3) cosФ = -√2/2 , cotФ = -1 ⇒ first answer

Step-by-step explanation:

* At first check the quadrant of the angle

∵ 180° < Ф < 270°

∴ Ф lies on the third quadrant

* Remember in the 3rd quadrant tanФ and cotФ only positive

∵ sinФ ≅ -0.7660

∵ tan²Ф = sec²Ф - 1

∵ secФ = 1/sinФ

∵ secФ = 1/-0.7660

∴ sec²Ф = (1/-0.7660)²

* Substitute this value in the equation

∴ tan²Ф = (1/-0.7660)² - 1 = 0.70428594 ⇒ take √ for both sides

∴ tanФ ≅ ± 0.8392

∵ Ф lies on the 3rd quadrant

∴ tanФ = 0.8392

* At first check the quadrant of the angle

∵ 0° < Ф < 90°

∴ Ф lies on the first quadrant

* Remember in the 1st quadrant all are positive

∵ sinФ = 21/29

∵ sin²Ф + cos²Ф = 1

∴ (21/29)² + cos²Ф = 1 ⇒ subtract (21/29)² from both sides

∴ cos²Ф = 1 - (21/29)² = 400/841 ⇒ take √ in both sides

∴ cosФ = ± 20/29

* Because Ф lies in the 1st quadrant

∴ cosФ = 20/29

* Remember that when the point is at the terminal side of angle Ф

∴ Its x-coordinate is cosФ

∴ Its y-coordinate is sinФ

* The point is (-√2/2 , √2/2)

∵ x-coordinate is negative ad y-coordinate is positive

∴ the point is on the 2nd quadrant

∴ 90° < Ф < 180°

∴ The values of sinФ and cscФ only positive

* From previous we know that:

∴ cosФ = -√2/2

∴ sinФ = √2/2

∵ cotФ = cosФ/sinФ

∴ cotФ = -√2/2 ÷ √2/2 = -√2/2 × 2/√2 = -√2/√2 = -1

* cosФ = -√2/2 , cotФ = -1

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3 years ago
For which pair of triangles would you use AAS to prove the congruence of the 2 triangles
DerKrebs [107]

Answer:

The correct option is B.

Step-by-step explanation:

According to AAS congruence rule, two triangles are congruent if two angles and a non included side are congruent to corresponding angles and side of another triangle.

We need two angles and a non included side, to use AAS postulate.

In option A, two sides and their inclined angle are congruent, therefore these triangles are congruent by SAS postulate and option A is incorrect.

In option B, two angles and a non included side are congruent, therefore these triangles are congruent by AAS postulate and option B is correct.

In option C, two angles and their included side are congruent, therefore these triangles are congruent by ASA postulate and option C is incorrect.

In option D, all sides are congruent, therefore these triangles are congruent by SSS postulate and option D is incorrect.

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Answer: 24 ft

Step-by-step explanation:

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