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Andre45 [30]
3 years ago
13

What is the lateral area of the prism? Assume the figure is resting on its base.

Mathematics
2 answers:
dolphi86 [110]3 years ago
8 0
Check the picture below.

the lateral area, namely the area of the sides, as you see in the picture, is really just the area of 6 rectangles.

front and back, two rectangles of 5x25,

left and right, two rectangles of 2x25.

simply get the area of each and sum them up, that's the lateral area of the prism.

\bf \stackrel{\textit{front and back}}{2(5\cdot 25)}~~~~+~~~~\stackrel{\textit{left and right}}{2(2\cdot 25)}

Liono4ka [1.6K]3 years ago
8 0
Your answer is 250 l*h*w
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ziro4ka [17]

Answer:

Step-by-step explanation:

1) You have to create an equation by combining like terms. In the first one, it shows that 5*x + 2 is the same as or equal to 17. So, 5x+2=17. Then, all you have to do it simplify. Move the apples and oranges over (the different terms) so you get 5x=17-2 (whenever you move the numbers across the = sign, it turns into the opposite). 5x=15. X=15/5. X=3

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5 0
3 years ago
If y varies directly as x and y = 3 when x = 24, find y when x = -16​
HACTEHA [7]

Answer:

-2

Step-by-step explanation:

y/x=constant

3/24=y/(-16)

y=-2

6 0
3 years ago
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SashulF [63]

Answer:

B.) Investing has the risk of losing principal, whereas saving does not.

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Many investment opportunities are governed by no such rules. The invested amount may be unavailable for perhaps a lengthy period of time, and any return on the investment may be dependent upon factors not under the control of the party accepting the money. There is the opportunity for complete loss of the invested amount, and the possibility of incurring additional liability in some cases.

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3 years ago
Jerry has a miniature model of a boat. He knows that the boat is 3 3/4 inches wide and 5 1/2 inches long. What is the actual len
FromTheMoon [43]

Width of the miniature model = 3\frac{3}{4} inches

Length of the miniature model = 5\frac{1}{2} inches

The actual width of the boat = 15 feet

Let us find the actual length of the boat.

Write it in a proportion form.

width of model : length of model : : width of actual : length of actual

$\Rightarrow 3\frac{3}{4}:5\frac{1}{2}::15:x

$\Rightarrow\frac{15}{4}:\frac{11}{2}::15:x

$\Rightarrow\frac{\frac{15}{4}}{\frac{11}{2}} =\frac{15}{x}

Do cross multiplication.

$\Rightarrow{\frac{15}{4}x =15\times\frac{11}{2}

$\Rightarrow{\frac{15}{4}x =\frac{165}{2}

$\Rightarrow x =\frac{165}{2}\times{\frac{4}{15}

⇒ x = 22

Hence the actual length of the boat is 22 feet.

6 0
3 years ago
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