Answer:
The repulsive electrostatic force between two of the protons is 14.4 N.
Explanation:
Given;
distance between the two protons, r = 4 x 10⁻¹⁵ m
charge of a proton, q = + 1.6 x 10⁻¹⁹ C
The repulsive electrostatic force between two of the protons is calculated by applying Coulomb's law;

Therefore, the repulsive electrostatic force between two of the protons is 14.4 N.
By doing this he increases the time due to which the rate of change momnetemdecreases. that means the ball comes to rest gently and does not hurt the fielder. but, if does not move his hand backwards, then the ball would come to rest in a fraction of second with a high rate of change of momentum. the ball will exert a lot of force on the hands of the fielder which will hurt him.
<span>sound waves are a type of wave sometimes called compression waves, vibrations with enough of an amplitude can compress and decompress the air adjacent to the object causing the waves to form.</span>
Answer:
The external force leads to an increase on gravitational and spring potential energies.
Explanation:
The system consists of a mass, resort and Earth. According to the Principle of Energy Conservation there is a potential energy as a consequence of the interaction between Earth and the mass and spring potential energy because of the spring deformation and, besides, the existence of work due to an external force:



![F\cdot \Delta r = G\cdot m \cdot M \cdot \left(\frac{1}{r_{o}-\Delta r}-\frac{1}{r_{o}} \right)+\frac{1}{2}\cdot k \cdot [(x_{o}+\Delta r)^{2} -x_{o}^{2}]](https://tex.z-dn.net/?f=F%5Ccdot%20%5CDelta%20r%20%3D%20G%5Ccdot%20m%20%5Ccdot%20M%20%5Ccdot%20%5Cleft%28%5Cfrac%7B1%7D%7Br_%7Bo%7D-%5CDelta%20r%7D-%5Cfrac%7B1%7D%7Br_%7Bo%7D%7D%20%20%20%5Cright%29%2B%5Cfrac%7B1%7D%7B2%7D%5Ccdot%20k%20%5Ccdot%20%5B%28x_%7Bo%7D%2B%5CDelta%20r%29%5E%7B2%7D%20-x_%7Bo%7D%5E%7B2%7D%5D)
The external force leads to an increase on gravitational and spring potential energies.