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Alla [95]
3 years ago
14

what are the two angles of a projection of a projectile moving with the velocity is 20m/s. so that the horizontal range is 45m​

Physics
1 answer:
GREYUIT [131]3 years ago
7 0

Answer:

Answer. So, the two Angles R :- 15° and 75° .

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An object starts at rest and accelerates at a rate of 4 m/s squared, how far does travel after 10 seconds
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40m/s2 because its already traveling 4m/s soo in 10 second it will be at 40 miles per seconds
4*10
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Which is the last step in conduction a Urlacher search
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Try the same search on a different data base.
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The ______________ scale has a single “anchor” point at the triple point of water.
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The "Temperature" scale has a single "anchor" point at the triple point of water.

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What will you use to measure the length of a copper wire of 50cm long?​
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BS33

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5 0
3 years ago
A particle with mass 1.81×10−3 kg and a charge of 1.22×10−8 C has, at a given instant, a velocity v⃗ =(3.00×104m/s)j^. What are
slava [35]

Answer:

The magnitude and direction of the acceleration of the particle is a= 0.3296\ \hat{k}\ m/s^2

Explanation:

Given that,

Mass m = 1.81\times10^{-3}\ kg

Velocity v = (3.00\times10^{4}\ m/s)j

Charge q = 1.22\times10^{-8}\ C

Magnetic field B= (1.63\hat{i}+0.980\hat{j})\ T

We need to calculate the acceleration of the particle

Formula of the acceleration is defined as

F = ma=q(v\times B)

a =\dfrac{q(v\times B)}{m}

We need to calculate the value of v\times B

v\times B=(3.00\times10^{4}\ m/s)j\times(1.63\hat{i}+0.980\hat{j})

v\times B=4.89\times10^{4}

Now, put the all values into the acceleration 's formula

a =\dfrac{1.22\times10^{-8}\times(-4.89\times10^{4}\hat{k})}{1.81\times10^{-3}}

a= -0.3296\ \hat{k}\ m/s^2

Negative sign shows the opposite direction.

Hence, The magnitude and direction of the acceleration of the particle is a= 0.3296\ \hat{k}\ m/s^2

7 0
3 years ago
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