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Archy [21]
3 years ago
10

What is true of both galvanic and electrolytic cells?

Chemistry
2 answers:
omeli [17]3 years ago
8 0

Answer:

reduction happens at the cathode

Explanation:

Just took the test.

Dmitrij [34]3 years ago
5 0

Answer:

Basically A.

Explanation:

A p E x

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What is the oxidation number of nitrogen in the nitrate ion NO31−?
ahrayia [7]

In No3-1 the oxidation number of oxygen is -5 so oxidation number of N would be +5

8 0
4 years ago
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Can anyone do these? I have 20 points for who ever can get them. I've completed everything else and these ones are what I'm stuc
8_murik_8 [283]
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8 0
3 years ago
Question 9 (1 point)
pantera1 [17]

Answer:

8 moles of C

Explanation:

From the question given above, the following equation was obtained:

3A + 2B —> 6C

From the equation above,

3 moles of A reacted to produce 6 moles of C.

Thus, the number of mole of C produced by reacting 4 moles of A can be obtained as follow:

From the equation above,

3 moles of A reacted to produce 6 moles of C.

Therefore, 4 moles of C will react to produce = (4 × 6)/3 = 8 moles of C

Thus, 8 moles of C can be obtained from the reaction of 4 moles of A with excess B

6 0
3 years ago
List emergency equipment, those are available in the laboratory?
mestny [16]

Answer:

Hands-free eyewash stations, sand bucket, fire blankets, fire extinguishers, fire alarm system and first aid kit.

Explanation:

Working in laboratories has many risks, therefore, preventive measures that should be incorporated to avoid the occurrence of any laboratory accidents.

Some of the important emergency equipment that should be available in laboratories are: hands-free eyewash stations, sand bucket, fire blankets, fire extinguishers, fire alarm system, chemical storage cabinet, first aid kits and fume hood.

Some of the personal protective equipment include lab coats, goggles, safety gloves and face shield.

7 0
3 years ago
Precipitation reactions: Hg(NO3)2(aq) +Na2CrO4(aq) = _________ (aq) + NaNO3 (s)
valina [46]
The completed and balanced equation is:
<span>Hg(N<span>O3</span><span>)2</span>+N<span>a2</span>Cr<span>O4</span>=HgCr<span>O4</span>+2Na(N<span>O3</span>)
Hope this helps :)</span>
5 0
3 years ago
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