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3 years ago

According to the first law of thermodynamics, what could happen when heat is added to a system?

2 answers:

8 0

B, since B claims that the heat is transferred, while A and D have energy decreasing or being destroyed and C has energy being created. First law of thermodynamics in layman terms: Energy can neither be created nor destroyed

DedPeter [7]3 years ago

8 0

Answer:

Explanation:

You might be interested in

Identify each statement that describes a benefit of the scientific method. (Select all choices that apply)

Alecsey [184]

The statements that describe a benefit of the scientific method are as follows:

It gives scientists a standardized way to approach a problem.
It reduces bias and judgment from personal experiences.
It gives scientists a common vocabulary for sharing information.

Thus, the correct options are B, C, and D.

<h3>What is the Scientific method?</h3>

The scientific method may be defined as a strategy of research in which a problem is recognized, relevant data is collected, a conjecture is composed of this data, and the assumption is empirically tested to determine the outcome of particular research.

The scientific method never explains or provides an answer to any question immediately because it consists of a scripted format with certain parameters.

The scientific method uses the identical vocabulary for sharing information with one another in particular terminology.

Therefore, it is well described above.

To learn more about the Scientific method, refer to the link:

brainly.com/question/17216882

#SPJ1

4 0

2 years ago

Calculate the acceleration of gravity as a function of depth in the earth (assume it is a sphere). You may use an average densit

Ber [7]

Solution :

Acceleration due to gravity of the earth, g $=\frac{GM}{R^2}$

$g=\frac{G(4/3 \pi R^2 \rho)}{R^2}=G(4/3 \pi R \rho)$

Acceleration due to gravity at 1000 km depths is :

$g=G\left(\frac{4}{3}\pi (R-d) \rho\right)$

$g=6.67 \times 10^{-11}\left(\frac{4}{3}\times 3.14 \times (6371-1000) \times 5.5 \times 10^3\right)$

$= 822486 \times 10^{-8}$

$=0.822 \times 10^{-2} \ km/s$

= 8.23 m/s

Acceleration due to gravity at 2000 km depths is :

$g=G\left(\frac{4}{3}\pi (R-d) \rho\right)$

$g=6.67 \times 10^{-11}\left(\frac{4}{3}\times 3.14 \times (6371-2000) \times 5.5 \times 10^3\right)$

$= 673552 \times 10^{-8}$

$=0.673 \times 10^{-2} \ km/s$

= 6.73 m/s

Acceleration due to gravity at 3000 km depths is :

$g=G\left(\frac{4}{3}\pi (R-d) \rho\right)$

$g=6.67 \times 10^{-11}\left(\frac{4}{3}\times 3.14 \times (6371-3000) \times 5.5 \times 10^3\right)$

$= 3371 \times 153.86 \times 10^{-8}$

= 5.18 m/s

Acceleration due to gravity at 4000 km depths is :

$g=G\left(\frac{4}{3}\pi (R-d) \rho\right)$

$g=6.67 \times 10^{-11}\left(\frac{4}{3}\times 3.14 \times (6371-4000) \times 5.5 \times 10^3\right)$

$= 153.84 \times 2371 \times 10^{-8}$

$=0.364 \times 10^{-2} \ km/s$

= 3.64 m/s

3 0

3 years ago

What does more damage; a slow semi truck, or a fast sports car

Goshia [24]

The fast sports car does more damage then the slow semi truck

7 0

3 years ago

A ball is thrown at 60 degrees and lands in 18.5 seconds what is the velocity of the ball at the start

n200080 [17]

Answer:

the initial velocity of the ball is 104.67 m/s.

Explanation:

Given;

angle of projection, θ = 60⁰

time of flight, T = 18.5 s

let the initial velocity of the ball, = u

The time of flight is given as;

$T = \frac{2u\times sin(\theta)}{g} \\\\2u\times sin(\theta) = Tg\\\\u = \frac{Tg}{2\times sin(\theta)} \\\\u = \frac{18.5 \times 9.8}{2\times sin(60^0)} \\\\u = 104.67 \ m/s$

Therefore, the initial velocity of the ball is 104.67 m/s.

3 0

3 years ago

A supertanker ( = 1.70 × 108 kg) is moving with a constant velocity. Its engines generate a forward thrust of 7.40 × 105 N. Dete

a_sh-v [17]

Answer:

(a) 0 (b) $F=1.67\times 10^9\ N$

Explanation:

Given that,

Mass of a supertanker, $m=1.7\times 10^8\ kg$

The engine of a generate a forward thrust of, $F=7.4\times 10^5\ N$

(a) As the supertanker is moving with a constant velocity. We need to find the magnitude of the resistive force exerted on the tanker by the water. It is given by :

F = ma, a is the acceleration

For constant velocity, a = 0

So, F = 0

(b) The magnitude of the upward buoyant force exerted on the tanker by the water is equal to the weight of the ship.

F = mg

$F=1.7\times 10^8\times 9.8\\\\F=1.67\times 10^9\ N$

Hence, this is the required solution.

4 0

3 years ago