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Arturiano [62]
3 years ago
13

According to the first law of thermodynamics, what could happen when heat is added to a system?

Physics
2 answers:
Burka [1]3 years ago
8 0
B, since B claims that the heat is transferred, while A and D have energy decreasing or being destroyed and C has energy being created. First law of thermodynamics in layman terms: Energy can neither be created nor destroyed
DedPeter [7]3 years ago
8 0

Answer:

B

Explanation:

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Determine the diameter of the largest circular hole that can be punched into a sheet of polystyrene 6 mm thick, knowing that the
Yakvenalex [24]

Answer:

43.41 mm

Explanation:

Given:

thickness of sheet, t = 6 mm

Force exerted by punch, F = 45 KN

Average shearing stress, T = 55 MPa

From average shearing stress T = Force F / Area A

Hence area = force/stress =45000/ 55 =818.18 mm^2

From area = pi*diameter*thickness

diameter = area/(pi* thickness)

= 818.18/(3.142*6)

= 43.41 mm

4 0
3 years ago
During spring semester at MIT, residents of the parallel buildings of the East Campus dorms battle one another with large catapu
natali 33 [55]

Answer:

110.7 J

Explanation:

Hooke's law is represented by the formula:

F = ke  where F is the force in Newton, K is force constant and e is extension in m

work done = 1/2ke² = 1/2 K ( e² - e₀²) and e₀ is the extension at relaxed length

e₀ =0

work done = 0.5 × 82N/m × (2.70 m)² = 110.7 J

4 0
3 years ago
A 35 grams bullet travels with a velocity of magnitude 126 km/h. What is the bullet's linear momentum?
LekaFEV [45]

Answer:

IDK

Explanation:

idk

3 0
3 years ago
Find the rms current delivered by the power supply when the frequency is very large. Answer in units of A.
Verizon [17]

Answer:

The rms current is 0.3112 A.

Explanation:

Given that,

Suppose, The capacitance is 170 μF and the inductance is 2.94 mH. The resistance in the top branch is 278 Ohms, and in the bottom branch is 151 Ohms. The potential of the power supply is 47 V .

We know that,

When the frequency is very large then the capacitance can be treated as a short circuit and inductance as open circuit.

So,

We need to calculate the rms current

Using formula of current

I=\dfrac{V}{R}

Where, V = voltage

R = resistance

Put the value into the formula

I=\dfrac{47}{151}

I= 0.3112 \ A

Hence, The rms current is 0.3112 A.

8 0
3 years ago
Find the ratio of intensities in 4 different sets of red to violet spectral satellites in Raman scattering spectra of CCl4 molec
Vlad1618 [11]

Complete Question

Find the ratio of intensities in 4 different sets of red to violet spectral satellites in Raman scattering spectra of CCl4 molecules at T=27C temperature if corresponding resonant infrared frequencies (equivalent to frequencies of nuclei vibrations) of CCl4 molecule are 217, 315, 457 and 774 cm-1 . (Note: Wavenumber N in cm-1 is defined as N=1/\lambda\  cm^{-1})

Answer:

The ratio of intensities is  I_1 : I_2 : I_3 : I_4 = 217 : 315 : 457 : 774

Explanation:

 From the question we are told that

        The number of sets of satellite is n = 4

        The temperature is  T = 27 ^oC

        The resonant infrared frequencies are f_1 = 217 cm^{-1}

                                                                          f_2 = 315 cm^{-1}

                                                                          f_3 = 457 cm^{-1}

                                                                          f_4 = 774 cm^{-1}

From the question we see that the wave number also has a unit ofcm^{-1} hence  the value of the wave numbers of the molecule are

                                                                            N_1 = 217 cm^{-1}                

                                                                          N_2 = 315 cm^{-1}

                                                                          N_3 = 457 cm^{-1}

                                                                          N_4 = 774 cm^{-1}

Generally intensity is mathematically represented as

             I = \frac{nhc}{A \lambda }

Here we see that  I varies inversely with wavelength  i,.e

         I \ \ \alpha \ \ \frac{1}{\lambda }              

From the question we are told that the wave number is mathematically represented as

         N  = \frac{1}{\lambda }

Therefore

          I \ \ \alpha \ \  N

This implies that  the ratio of intensity in first set to that of second set to that of third set to that of fourth set is  equal to the ratio of the wavenumber in the first set to that of the second set  to that of third set to that of fourth

     This is mathematically represented as

               I_1 : I_2 : I_3 : I_4 = N_1 : N_2 : N_3 : N_4

Substituting values

        I_1 : I_2 : I_3 : I_4 = 217 : 315 : 457 : 774

                     

5 0
3 years ago
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