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zzz [600]
3 years ago
9

A uniform ladder is 10 m long and weighs 400 n. it rests with its upper end against a frictionless vertical wall. its lower end

rests on the ground and is prevented from slipping by a peg driven into the ground. the ladder makes a 30◦ angle with the horizontal. the magnitude of the force exerted on the peg by the ladder is:

Physics
1 answer:
valkas [14]3 years ago
6 0
Check the attached file for the answer.

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Answer:

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How to find a planet’s gravitational field strength using its radius?
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The gravitational field strength is approximately equal to 10 N.

<u>Explanation:</u>

Gravitational field strength is the measure of gravitational force acting on any object placed on the surface of the planet. Generally, the mass of the object is considered as 1 kg.

So the gravitational field strength will be equal to the gravitational force acting on the object.

The formula for gravitational field strength is

g = \frac{F}{m}

Here g is the gravitational field strength, m is the mass of the object placed on the surface and F is the gravitational force acting on the object.

Since, the mass of any object placed on the surface of earth will be negligible compared to the mass of Earth, so the mass of the object is considered as 1 kg.

Then the g = F

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Here G is the gravitational constant, M is the mass of Earth and m is the mass of the object placed on the surface, while r is the radius of the Earth.

g = F = \frac{6 \times 10^{24} \times 6.67 \times 10^{-11}  \times 1}{(6.6 \times 10^{6}) ^{2} }

g = 0.977 \times 10^1= 9.77\ N

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Darw a velocity time graph for body moving with uniform acceleration
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ioda

Answer:

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