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Answer:
e. 27 rho.
Explanation:
The density of an object, assumed constant, is defined as the relationship between the mass and the volume.
If the object is compressed in such a way that the diameter is reduced to 1/3, this means, that the radius will be reduced in the same proportion.
Now, if the mass remains the same (the compression can't change it) , the volume (assumed to be a perfect sphere) will be reduced also:
V₀ = 4/3*π*r³
Vf= 4/3*π*(r/3)³ = 4/3*π*(r³/27) = V₀/27
As the volume is in in the denominator of the expression for density, this means that the new density will be equal to 27 times the original one:
ρ₀ = m/ V₀
ρ₁ = m/ V₁ = m/ (V₀/27) = 27* (m/V₀) = 27*ρ₀
Answer:
A.
Explanation:
The flux through the Gaussian sphere of radius centered at the origin,
Therefore:
φ
charge:
,
φ=
substitute the values
φ=
φ=
The frequency of the wave is determined as 7.96 Hz.
<h3>
Frequency of the wave</h3>
The frequency of the wave is calculated as follows;
y = A sin(ωt - kx)
where;
- A is amplitude of the wave
- ω is angular speed of the wave
ω = 2πf
f = ω/2π
f = (50)/(2π)
f = 7.96 Hz
Thus, the frequency of the wave is determined as 7.96 Hz.
Learn more about frequency of waves here: brainly.com/question/6297363
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