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bagirrra123 [75]
2 years ago
8

A proton of mass m moving with a speed of 3.0 × 106 m/s undergoes a head on elastic collision with an alpha particle of mass 4m

at rest. What are the velocities of the two particles after the collision?
Physics
1 answer:
Sergio039 [100]2 years ago
4 0

Answer:6.0×10^5m/s

Explanation:

According to the law of conservation of momentum, sum of the momenta of the bodies before collision is equal to the sum of their momenta after collision.

After their collision, the two bodies will move with a common velocity (v)

Momentum = mass × velocity

Let m1 be the mass of the proton = m

Let m2 be the mass of the alpha particle = m2

Let v1 be the velocity of the proton = 3.0×10^6m/s

Let v2 be the velocity of the alpha particle = 0m/s (since the body is at rest).

Using the law,

m1v1 + m2v2 = (m1 + m2)v

m(3.0×10^6) + 4m(0) = (m + 4m)v

m(3.0×10^6) = 5mv

Canceling 'm' at both sides,

3.0×10^6 = 5v

v = 3.0×10^6/5

The common velocity v = 6.0×10^5m/s

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xxTIMURxx [149]

Answer:

6.00 x 10⁻⁸N

Explanation:

Given parameters:

Mass of each dump trucks  = 1500kg

Distance between them  = 50m

Unknown:

New gravitational force between them = ?

Solution:

From Newton's law of universal gravitation,

        F = \frac{G m1 m2}{r^{2} }  

F is the gravitational force

G is the universal gravitation constant

m is the mass

r is the distance

           F  = \frac{6.67 x 10^{-11} x 1500  x 1500}{50^{2} }    = 6.00 x 10⁻⁸N

4 0
2 years ago
According to Newton's first law, an object at rest will _____.
Vesnalui [34]
Stay at rest unless moved my force! :)
8 0
2 years ago
A tennis player swings her 1000 g racket with a speed of 12 m/s. she hits a 60 g tennis ball that was approaching her at a speed
tensa zangetsu [6.8K]

Answer:

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Explanation:

6 0
3 years ago
Question 4 (1 point)
NNADVOKAT [17]

Answer: 0.42 Amperes

Explanation:

Given that:

Current, I = ?

Electric charge Q = 100 coulomb

Time, T = 4.0 minutes

(The SI unit of time is seconds. so, convert 4.0 minutes to seconds)

If 1 minute = 60 seconds

4.0 minutes = 4.0 x 60 = 240 seconds

Since electric charge, Q = current x time

i.e Q = I x T

100 coulomb = I x 240 seconds

I = 100 coulomb / 240 seconds

I = 0.4167 Amperes (round to the nearest hundredth which is 0.42 amperes)

Thus, 0.42 Amperes of current flows in the circuit.

6 0
3 years ago
A 6.8 kg bowling ball and 7.4 kg bowling ball rest on a rack 0.74 m apart. What is the force of gravity pulling each ball toward
zimovet [89]

The gravitational force between the two balls is 6.13\cdot 10^{-9} N

Explanation:

The magnitude of the gravitational force between two objects is given by:

F=G\frac{m_1 m_2}{r^2}

where :

G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2} is the gravitational constant

m1, m2 are the masses of the two objects

r is the separation between the objects

For the balls in this problem,  we have

m_1 = 6.8 kg

m_2 = 7.4 kg

r = 0.74 m

Substituting into the equation, we find the gravitational force between the two balls:

F=(6.67\cdot 10^{-11})\frac{(6.8)(7.4)}{(0.74)^2}=6.13\cdot 10^{-9}N

Learn more about gravitational force:

brainly.com/question/1724648

brainly.com/question/12785992

#LearnwithBrainly

4 0
3 years ago
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