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3 years ago

13

Water molecules have unique physical and chemical properties that enable them to perform important functions in living organisms

. What property of water molecules is specifically caused by their polarity?

1 answer:

Serhud [2]3 years ago

4 0

Answer: cohesion

Explanation:

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3 years ago

How do you get the products of KCIO3

Elden [556K]

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2KClO3 -> 302 + 2KCl

Explanation:

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3 years ago

What is discriminate?

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To make a distinction in favor of or against a person or thing on basic or group, class or category, to which the person or thing(s) belong

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4 years ago

If our eyes could see a slightly wider region of the electromagnetic spectrum, we would see a fifth line in the Balmer series em

erica [24]

Answer: Wavelength associated with the fifth line is 397 nm

Explanation:

$E=\frac{hc}{\lambda}$

$\lambda$ = Wavelength of radiation

E= energy

For fifth line in the H atom spectrum in the balmer series will be from n= 2 to n=7.

Using Rydberg's Equation:

$\frac{1}{\lambda}=R_H\left(\frac{1}{n_i^2}-\frac{1}{n_f^2} \right )\times Z^2$

Where,

$\lambda$ = Wavelength of radiation

$R_H$ = Rydberg's Constant = $10973731.6m^{-1}$

$n_f$ = Higher energy level = 7

$n_i$ = Lower energy level = 2 (Balmer series)

Putting the values, in above equation, we get

$\frac{1}{\lambda}=10973731.6\times \left(\frac{1}{2^2}-\frac{1}{7^2} \right )\times 1^2$

$\frac{1}{\lambda}=2.52\times 10^{6}m$

$\lambda}=3.97\times 10^{-7}m=397 nm$ $1nm=10^{-9}m$

Thus wavelength λ associated with the fifth line is 397 nm

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4 years ago

Question 4<br> How many carbon-carbon triple bonds are present in a molecule of 4,5-diethyloctane?

ivann1987 [24]

Answer:

We will have zero bonds

Explanation:

In this case, we have to start with the <u>structure of 4,5-diethyloctane</u>. This name ends with the <u>suffix "ane"</u> therefore we have an <u>alkane</u>. All the alkanes are made with <u>single bonds</u> between carbons and <u>single bonds</u> between carbon and hydrogen.

The molecule will have a <u>carbon chain of eight carbons</u> and we will have 2 <u>branches</u>, one ethyl on carbon 4 and another ethyl on carbon 5. (see figure 1)

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3 years ago