Answer:- 14.0 moles of hydrogen present in 2.00 moles of ![[tex]C_6H_7N](https://tex.z-dn.net/?f=%20%5Btex%5DC_6H_7N)
.
Solution:- We have been given with 2.00 moles of 
and asked to calculate the grams of hydrogen present in it. It's a two step conversion problem. In first step we convert the moles of the compound to moles of hydrogen as one mol of the compound contains 7 moles of hydrogen. In next step the moles are converted to grams on multiplying the moles by atomic mass of H. The calculations are shown as:
= 14.0 g H
So, there are 14.0 g of hydrogen in 2.00 moles of .
Anomalous data on a graph would show up as say a very high or very low value which does not fit in with the normal values which may be background values.If it was a straight line graph then the anomalous point would plot well above or below the line or if it was a bar graph ie a histogram it would be much higher or lower than the surrounding data. In mineral exploration, anomalies are looked for in say geophysics or geochemistry data values for high or low magnetism or conductivity or high chemical values indicating the presence of valuable minerals at that point.
Answer: B:
Explanation:
This is the most reasonable answer
Answer:
The formal charge on nitrogen in 
is +1.
Explanation:
The structure of is as follows.
(In attachment)
From the structure, Nitrogen has no non bonding electrons. Nitrogen has four bonds and each bond corresponds to 2 electrons. Hence, nitrogen have eight bonding electrons and five valence electrons.
![Formal\,charge\,on\,nitrogen = 5-[0+ \frac{8}{2}]= +1](https://tex.z-dn.net/?f=Formal%5C%2Ccharge%5C%2Con%5C%2Cnitrogen%20%3D%205-%5B0%2B%20%5Cfrac%7B8%7D%7B2%7D%5D%3D%20%2B1)
Therefore, The formal charge on nitrogen in is +1.
