Answer: 12.78ml
Explanation:
Given that:
Volume of KOH Vb = ?
Concentration of KOH Cb = 0.149 m
Volume of HBr Va = 17.0 ml
Concentration of HBr Ca = 0.112 m
The equation is as follows
HBr(aq) + KOH(aq) --> KBr(aq) + H2O(l)
and the mole ratio of HBr to KOH is 1:1 (Na, Number of moles of HBr is 1; while Nb, number of moles of KOH is 1)
Then, to get the volume of a 0.149 m potassium hydroxide solution Vb, apply the formula (Ca x Va)/(Cb x Vb) = Na/Nb
(0.112 x 17.0)/(0.149 x Vb) = 1/1
(1.904)/(0.149Vb) = 1/1
cross multiply
1.904 x 1 = 0.149Vb x 1
1.904 = 0.149Vb
divide both sides by 0.149
1.904/0.149 = 0.149Vb/0.149
12.78ml = Vb
Thus, 12.78 ml of potassium hydroxide solution is required.
Answer:
They attract or repel other charged objects without touching them.
Explanation:
My chemistry teacher always says like repels like opposite attracts.
Answer:
The answer is 3
C2H5OH + O2 CO2 +H2O (unbalanced)
C2H5OH +3O2(g). 2CO2(g)+3H2O(balanced)
So it contains three protons and four neutrons
Answer:
The intermediate is carbocation.
Explanation:
The reaction of alkene with an acid to give alcohol is an electrophilic addition reaction.
In electrophilic reaction, the alkene is being attacked by an alkene.
in case of aqueous acid reaction with alkene , the electrophile is [H⁺].
When the proton attacks the alkene it generates carbocation.
The carbocation generated is formed based on stability of carbocation.
The mechanism is shown in the figure.
