Question

A sphere has a net charge of 8.11 nC, and a negatively charged rod has a charge of −6.13 nC. The sphere and the rod undergo a process such that 4.20 ✕ 109 electrons are transferred from the rod to the sphere. What are the charges of the sphere and the rod after this process?

Answer 1

Answer:

Charge of the sphere = $7.44 * 10^{-9} C$

Charge of the rod = $-5.46 * 10^{-9} C$

Explanation:

Parameters given:

Initial charge of sphere = 8.11 nC = $8.11 * 10^{-9} C$

Initial charge of rod = -6.13 nC = $-6.13 * 10^{-9} C$

In the process, the rod lost $4.20 * 10^{9} C$. We have to find the charge of these electrons. Then, we subtract it from the rod's initial charge to get its final charge and add it to the sphere's initial charge to get its final charge.

Charge of $4.20 * 10^{9} C$ electrons = electronic charge * number of electrons

           = $4.20 * 10^9 * (-1.6023 * 10^{-19}) C$

     

           = $-6.73 * 10^{-10} C$

FINAL CHARGE OF ROD

Final charge of rod = $-6.13 * 10^{-9} C$ - ($-6.73 * 10^{-10} C$)

                                = $-5.46 * 10^{-9} C$

FINAL CHARGE OF SPHERE

Final charge of sphere = $8.11 * 10^{-9} C$ + ($-6.73 * 10^{-10} C$)

                                      = $7.44 * 10^{-9} C$