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vagabundo [1.1K]
2 years ago
5

A worker pushes horizontally on a large crate with a force of 265.0 N and the crate moved 4.3 m. How much work was done?

Physics
1 answer:
trapecia [35]2 years ago
8 0

Answer:

<h2>1139.5 J</h2>

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question we have

work done = 265 × 4.3 = 1139.5

We have the final answer as

<h3>1139.5 J</h3>

Hope this helps you

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A 25.0kg girl pushes a 50.0kg boy so that he accelerates at 4.00m/s2. What is the force of the boy on the girl? A. 200N B. 100N
Fynjy0 [20]

Answer:

a

Explanation:

so the answer is 200N

and I hope it is correct

8 0
3 years ago
If the absolute temperature of a gas is 600 K, the temperature in degrees Celsius is: A. 705°C. B. 873°C. C. 273°C. D. 327°C
zlopas [31]

Answer:

D). 327 ^0 C

Explanation:

As we know that temperature scale is linear so we will have

\frac{^0C - 0}{100 - 0} = \frac{K - 273}{373 - 273}

now we have

\frac{^0 C - 0}{100} = \frac{K - 273}{100}

so the relation between two scales is given as

^0 C = K - 273

now we know that in kelvin scale the absolute temperature is 600 K

so now we have

T = 600 - 273 = 327 ^0 C

so correct answer is

D). 327 ^0 C

4 0
3 years ago
A gazelle is running at 17.46 m/s. He sees a lion and accelerates at -1.49 m/s/s,
Vsevolod [243]

Answer:

V=21.0211m/s

Explanation:

Use V=vi+at

So, V=17.46m/s+(1.49m/s^{2})(2.39s)= 21.0211m/s

5 0
2 years ago
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A research submarine has a 30-cm-diameter window that is 8.1 cm thick. The manufacturer says the window can withstand forces up
malfutka [58]

The pressure at a certain depth underwater is:

P = ρgh

P = pressure, ρ = sea water density, g = gravitational acceleration near Earth, h = depth

The pressure exerted on the submarine window is:

P = F/A

P = pressure, F = force, A = area

The area of the circular submarine window is:

A = π(d/2)²

A = area, d = diameter

Set the expressions for the pressure equal to each other:

F/A = ρgh

Substitute A:

F/(π(d/2)²) = ρgh

Isolate h:

h = F/(ρgπ(d/2)²)

Given values:

F = 1.1×10⁶N

ρ = 1030kg/m³ (pulled from a Google search)

g = 9.81m/s²

d = 30×10⁻²m

Plug in and solve for h:

h = 1.1×10⁶/(1030(9.81)π(30×10⁻²/2)²)

h = 1540m

5 0
3 years ago
Which best explains why the shapes of a liquid can change
stiv31 [10]
The shape of a liquid can change because the atoms in it are not close together to form a solid, they flow freely.
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