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marissa [1.9K]
3 years ago
12

What point does a basketball have the greatest potential energy

Physics
2 answers:
tester [92]3 years ago
7 0

Point C

At this point, which is the highest point, all of the ball's energy is gravitational potential energy. The ball does not have kinetic energy because it is not moving at this point.


Semenov [28]3 years ago
4 0
When it’s about to be dropped
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PLEASE HELP!!!!
Snezhnost [94]

Answer:

the cognitive abilities of an individual to learn from experience to reason well, and to cope effectively with the demands of daily living

Explanation:

Yes that can be understood by a simple example

Suppose two people are in exam

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4 0
2 years ago
Read 2 more answers
A car traveling at 38 m/s starts to decelerate steadily. It comes to a complete stop in 10 seconds. What is its acceleration?
asambeis [7]

a=v/t

a=38/10

a=-3.8 m/s^2

You put the negative in front of 3.8 because it decelerated.

Hope it helps and is correct :)

6 0
3 years ago
A mother and daughter are on a seesaw in the park. How far from the center must the 160.9lb mother sit in order to balance the 6
Soloha48 [4]

Answer:

The mother has to sit 2.17 ft from the center on the other side of the seesaw.

Explanation:

We are trying to find the sum of torques given by the weights of mother and daughter to be zero.

If the torque of the daughter on one side of the pivoting point is given by:

5.5 ft x 63.5 lb x g = 349.25 g ft lb

we need that the absolute value of the torque exerted by the mom (160.9 lb) to be the same in magnitude (and of course opposite direction). So we assume that "d" is the distance at which the mother locates to make this torque equal in magnitude to her daughter's torque:

d x 160.9 lb x g = 349.25 g ft lb

d = 2.17 ft

3 0
3 years ago
An astronaut drops a rock from the top of a crater on the moon. When the rock is halfway down to the bottom of the crater, its s
Alexxx [7]

Answer: vf1/vf2= 1/ sqrt(2)

Explanation :on the moon no drag force so we have only the  force of gravity. aceleration is g(moon)= 1.62m/s2.the rest is basic kinematics

if the rock travels H to the bottom we can calculate velocity:

vo=0m/s (drops the rock)  , yo=0

vf*vf= vo*vo+2g(y-yo)

when the rock is halfway  y = H/2 so:

vf1*vf1=2*g*H/2 so vf1 = sqrt(gH)

when the rock reach the bottom y=H so:

vf2*vf2=2*g*H so vf2 = sqrt(2gH)

so vf1/vf2= 1/ sqrt(2)

good luck from colombia

8 0
3 years ago
Read 2 more answers
Please help
Snezhnost [94]

Answer:

Range = 22.61 m

Explanation:

We can use the formula for the Range in flat ground, given by:

Range=v_i^2\frac{sin(2\theta)}{g}

which for our case renders:

Range=15^2\frac{sin(80^o)}{9.8} \approx 22.61\,\,m

4 0
2 years ago
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