4 years ago

What point does a basketball have the greatest potential energy

2 answers:

7 0

Point C

At this point, which is the highest point, all of the ball's energy is gravitational potential energy. The ball does not have kinetic energy because it is not moving at this point.

Semenov [28]4 years ago

4 0

When it’s about to be dropped

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F=mass x what does this equal?

ikadub [295]

Answer:

Force = mass × acceleration.

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3 years ago

A wire of resistance 5.9 Ω is connected to a battery whose emf ε is 4.0 V and whose internal resistance is 1.2 Ω. In 2.9 min, ho

dexar [7]

Answer:

a) 390J

b) 322J

c) 68J

Explanation:

We need to calculate the power given by the battery. the power is given by:

$P=V*I\\I=\frac{V}{R}\\I=\frac{4}{5.9+1.2}\\I=0.56A\\P=2.24W$

Watts is J/s so:

$E=P*t\\E=2.24\frac{J}{s}*2.9min*(60\frac{s}{min})=390J$

The thermal energy in the wire is given by:

$E_w=P_w*t\\P_w=I^2*R_w=0.56^2*5.9=1.85W\\E_w=1.85\frac{J}{s}*2.9min*(60\frac{s}{min})=322J$

And the the dissipated thermal energy in the battery will be the remainig energy:

$E_b=E-E_w\\E_b=390-322=68J$

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4 years ago

An athlete walks 8 meters East , 2 meters South, 8 meters West, and finally 2 meters North. What is the total distance traveled?

serg [7]

Explanation:

20 meters is travelled by him

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2 years ago

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A person on a bicycle travels a distance of 12.5 km in 2.1 hrs, what was the speed of the person on the bicycle?

Leona [35]

Answer:

5.9 km/hour

Explanation:

divide 12.5 by 2.1 and the answer is 5.9

8 0

2 years ago

Two 2 kg masses is placed at either end of a rod that has a mass of .5 kg and a length of 3 m. What is the moment of inertia if

sergij07 [2.7K]

Explanation:

a) $I=\displaystyle \sum_{i}m_ir_i^2$

where $r_i$ is the distance of the mass $m_i$ from the axis of rotation. When the axis of rotation is placed at the end of the rod, the moment of inertia is due only to one mass. Therefore,

$I= mr^2 = (2\:kg)(3\:m)^2 = 18\:kg-m^2$

b) When the axis of rotation is placed on the center of the rod, the moment is due to both masses and the radius r is 1.5 m. Therefore,

$\displaystyle I= \sum_{i}m_ir_i^2 = 2(2\:kg)(1.5\:m)^2 = 9\:kg-m^2$

7 0

3 years ago