Explanation:
An acid is a substance that produces excess hydroxonium ions in solution.
An acid based on the pH scale is a substance that has a low pH. Acid lies within a range of 1-7 on the pH scale.
- A pH of 7 is for neutral compounds like water.
- A pH greater that 7 is for basic compounds.
- In order to raise the pH, we are driving at a substance becoming more neutral or basic.
This can be achieved by adding more base to the solution of the substance. When we add more base, hydroxyl ions will neutralize the excess hydroxonium ions and drag the pH towards that of neutrality.
Addition of more base can eventually make the substance basic.
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Answer:
Density rectangular block = 7.47 (Approx) gm/cm³
Explanation:
Given:
Length = 8.335 cm
Width = 1.02 cm
Height = 0.982 cm
Mass = 62.3538 gm
Find:
Density rectangular block
Computation:
Volume of block = lbh
Volume of block = (8.335)(1.02)(0.982)
Volume of block = 8.3486 cm³
Density = Mass / Volume
Density rectangular block = 62.3538 / 8.3486
Density rectangular block = 7.47 (Approx) gm/cm³
Answer:
they have delocolised electrons which can carry electrical charges through the metals.
Explanation:
Answer:
The rate determining step depends on the
Explanation:
The rate determining step depends on the mechanism of the reaction. If it proceeds by E1 reaction mechanism, it produces 1-methylcyclohexene while the E3 reaction mechanism gives 3-methylcyclohexene. The rate determining step for E1 is an intermediate that is formed when protonation of the hydroxyl group occurs to form H3O+ followed by electrophilic attack on the carbocation formed to absorb the hydrogen making the carbon atom -CH2 and forming a double bond between.
The E3 mechanism is similar only that the attack on the carbon atom is done at the -C3 instead of -C1.
Answer:
0.11M
Explanation:
What is the Molarity of a Ca(OH)2 solution if 30.0mL of
the solution is neutralized by 26.4mL of 0.25M HCI solution?
1L (1000 ml) of the HCl contains 0.25 moles of H ion
26.4 ml contains ( 26.4 X0.25/1000) moles of H ion ion
=0.0066 moles H ion
2HCl +Ca (OH)2-----> 2H2O +CaCl2
SO 2 H IONS NEUTRALIZE 1 Ca(OH)2 MOLECULE
00066 moles H ion neutralize 0.0033 moles Ca(OH)2
the 0.0033 moles are distributed over 30 ml, so the concentration of the
Ca(OH)2 IS 0,0033/(30/1000) =0.11 moles/liter or 0.11M