A train can speed up at a uniform rate of 0.15 m/s2. In what minimum distance can

Physics

1 answer:

goblinko [34]4 years ago

3 0

Answer:

d = 2083.33 m

Explanation:

Given that,

Acceleration of the train, a = 0.15 m/s²

The initial speed of the car, u = 0\

Final velocity, v = 25 m/s

We need to find the minimum distance covered by the train. Let it is d. Using third equation of kinematics as follows :

$v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{(25)^2-0}{2\times 0.15}\\\\d=2083.33\ m$

So, the minimum distance is 2083.33 m

You might be interested in

At one end of a production line, Isaac puts peaches into cans on a conveyor belt. He fills 18 cans per minute. As soon as Isaac

AURORKA [14]

Answer: Long answer...

<em>Explanation:</em> As soon as Isaac has filled 670 cans on the conveyor belt, Albert starts putting lids on the cans at the other end of the production line. As Albert finishes closing each can, he moves up along side the conveyor belt to meet the next can. Albert puts lids on 50 cans per minute.

8 0

3 years ago

At the nose of a missile in flight, the pressure and temperature are 5.6 atm and 850°R, respectively. Calculate the density and

Contact [7]

To solve this problem we will apply the definition of the ideal gas equation, where we will clear the density variable. In turn, the specific volume is the inverse of the density, so once the first term has been completed, we will simply proceed to divide it by 1. According to the definition of 1 atmosphere, this is equivalent in the English system to

$1atm = 2116lb/ft^2$