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Afina-wow [57]
3 years ago
7

A 750 Watt hairdryer is used for 15 minutes. Calculate the Kwhr used. Calculate the cost to use 15 min. every day for 1 year @ 8

cents/Kwhr
Physics
2 answers:
Rufina [12.5K]3 years ago
8 0
Part (a):
We know that:
1 kw = 1000 watt ..........> Therefore, to convert watt into kw, we will divide by 1000
1 hour = 60 min ..........> Therefore, to convert mins into hours, we will divide by 60
Based on the above, the conversion results for the two units together would be as follows:
1 watt minute is equivalent to <span>0.000017 kilowatt hours
</span>Now, for the given , we will simply use cross multiplication to do the conversion as follows:
1 watt minute..............> 0.000017 kilowatt hours
750*15 ................> ??
750*15 watt min = 0.19125 kilowatt hour

Part (b):
From part a, we have that the consumption is 0.19125 kilowatt hour per day. Assuming that the year is 365 days, we would have:
yearly consumption = 0.19125 * 365 = 69.80625 kilowatt hour
The cost is 8 cents/kilowatt hour
Therefore:
yearly cost = 69.80625 * 8 = 558.45 cents

Hope this helps :)

rusak2 [61]3 years ago
8 0

Answer:

1) 0.1875 kWhr

2) $5.475

Explanation:

1) To convert 750 Watt to kWhr, firts we convert watt to kilowatt

750 W in kW = \frac{750}{1000}  = 0.75kW

To calculate the amount of power used in kWhr, we multiply the power rating (0.75 kW) by the number of time spent in hours (15 mins).

To convert 15 mins to hour,

15 mins in hr = \frac{15}{60} = 0.25hr

The kWhr used = 0.75 x 0.25 = 0.1875 kWhr

2) If used 15 mins everyday for a year, first we calculate the total amount of power used for 365 days

Daily usage at 15 mins = 0.1875 kWhr

Yearly usage = 0.1875 x 365 = 68.4375 kWhr

Cost of usage for a year at 8 cents per kWhr is;

68.4375 x 8 = 547.5 cents

Cost of usage = $5.475 per year

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Alpha particles Ichargeq q = + 2e mass m=6.8*10^ -27 kg) at 17*10^ 4 m/s What magnetic field strength would be required to bend them into a circular path of radiuse c = 0.25m ok

3 0
3 years ago
A hockey puck on a frozen pond is given an initial speed of 20.0 m/s. If the puck always remains on the ice and slides 115 m bef
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μ_k = 0.1773

Explanation:

We are given;

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F_k = μ_k•N

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Since gravity acts in the negative direction, the normal force will be positive.

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Thus,equating equation 1 and 2,we have;

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