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Afina-wow [57]
3 years ago
7

A 750 Watt hairdryer is used for 15 minutes. Calculate the Kwhr used. Calculate the cost to use 15 min. every day for 1 year @ 8

cents/Kwhr
Physics
2 answers:
Rufina [12.5K]3 years ago
8 0
Part (a):
We know that:
1 kw = 1000 watt ..........> Therefore, to convert watt into kw, we will divide by 1000
1 hour = 60 min ..........> Therefore, to convert mins into hours, we will divide by 60
Based on the above, the conversion results for the two units together would be as follows:
1 watt minute is equivalent to <span>0.000017 kilowatt hours
</span>Now, for the given , we will simply use cross multiplication to do the conversion as follows:
1 watt minute..............> 0.000017 kilowatt hours
750*15 ................> ??
750*15 watt min = 0.19125 kilowatt hour

Part (b):
From part a, we have that the consumption is 0.19125 kilowatt hour per day. Assuming that the year is 365 days, we would have:
yearly consumption = 0.19125 * 365 = 69.80625 kilowatt hour
The cost is 8 cents/kilowatt hour
Therefore:
yearly cost = 69.80625 * 8 = 558.45 cents

Hope this helps :)

rusak2 [61]3 years ago
8 0

Answer:

1) 0.1875 kWhr

2) $5.475

Explanation:

1) To convert 750 Watt to kWhr, firts we convert watt to kilowatt

750 W in kW = \frac{750}{1000}  = 0.75kW

To calculate the amount of power used in kWhr, we multiply the power rating (0.75 kW) by the number of time spent in hours (15 mins).

To convert 15 mins to hour,

15 mins in hr = \frac{15}{60} = 0.25hr

The kWhr used = 0.75 x 0.25 = 0.1875 kWhr

2) If used 15 mins everyday for a year, first we calculate the total amount of power used for 365 days

Daily usage at 15 mins = 0.1875 kWhr

Yearly usage = 0.1875 x 365 = 68.4375 kWhr

Cost of usage for a year at 8 cents per kWhr is;

68.4375 x 8 = 547.5 cents

Cost of usage = $5.475 per year

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Answer:

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Explanation:

(a)

Change in mechanical energy equals change in kinetic energy

Kinetic energy is given by0.5mv^{2}

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Since he finally comes to rest, final kinetic energy is zero because the final velocity is zero

Change in kinetic energy is given by final kinetic energy- initial kinetic energy hence

0-472.305  J=-472.305  J

(b)

From fundamental kinematic equation

v^{2}=u^{2}+2as

Where v and u are final and initial velocities respectively, a is acceleration, s is distance

Making s the subject we obtain

s=\frac {v^{2}-u^{2}}{-2a} but a=\mu g hence

s=\frac {v^{2}-u^{2}}{-2\mu g}=\frac {0^{2}-3.7^{2}}{-2*0.7*9.81}=0.996796272\approx 1 m

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Answer:

Approximately 3.1 \times 10^4 \; \rm N (assuming that the acceleration due to gravity is g = 9.81\; \rm kg \cdot N^{-1}.)

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Similarly, let F_1 and F_2 denote the size of the force on the two pistons. Since the person is placing all her weight on the first piston:

F_1 = W = m \cdot g = 50\; \rm kg \times 9.81 \; \rm kg \cdot N^{-1} =495\; \rm N.  

Since both pistons fit into cylinders, the two contact surfaces must be circles. Keep in mind that the area of a square is equal to \pi times its radius, squared:

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By Pascal's Law, the pressure on the two pistons should be the same. Pressure is the size of normal force per unit area:

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For the pressures on the two pistons to match:

\displaystyle \frac{F_1}{A_1} = \frac{F_2}{A_2}.

F_1, A_1, and A_2 have all been found. The question is asking for F_2. Rearrange this equation to obtain:

\displaystyle F_2 = \frac{F_1}{A_1} \cdot A_2 = F_1 \cdot \frac{A_2}{A_1}.

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\begin{aligned}F_2 &= F_1 \cdot \frac{A_2}{A_1} \\ &= 495\; \rm N \times \frac{2.25\, \pi\; \rm cm^2}{144\, \pi \; \rm cm^2} \approx 3.1 \times 10^4\; \rm N\end{aligned}.

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Answer:

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Explanation:

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\Sigma F_{x} = F_{F}\cdot \cos \theta_{F} + F_{St,x} = 0 (1)

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If we know that F_{F} = 20\,N, F_{Sp} = 30\,N and \theta_{F} = 63^{\circ}, then the components of the force done by Steinberg on the chewing toy is:

F_{St,x} = -F_{F}\cdot \cos \theta_{F}

F_{St,x} = -(20\,N)\cdot \cos 63^{\circ}

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The magnitud of the force is determined by Pythagorean Theorem:

F_{St} = \sqrt{F_{St,x}^{2}+F_{St,y}^{2}}

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\theta_{St} = 180^{\circ} + \tan^{-1} \left(\frac{F_{St,y}}{F_{St,x}}\right)

\theta_{St} = 180^{\circ} + \tan^{-1} \left(\frac{12.180\,N}{-9.080\,N}\right)

\theta_{St} \approx 126.704^{\circ}

The magnitude and direction of the force applied by Steinberg are approximately 15.192 newtons and 126.704º.

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Answer:

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