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lyudmila [28]
3 years ago
11

A student practicing for a track meet ran 250 m in 30 seconds. What was her average speed?

Physics
1 answer:
DochEvi [55]3 years ago
6 0

Answer:

8.33 meters/sec.

Explanation:

distance = 250 meters

time = 30 sec.

velocity = distance / time

            = 250 meters

                   30 sec.

            = 8.33 meters/sec.

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A 2.7-kg ball is thrown upward with an initial speed of 20.0 m/s from the edge of a 45.0 m high cliff. At the instant the ball i
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Answer:

The distance traveled by the woman is 34.1m

Explanation:

Given

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y = yo + ut -1/2gt²

u = 20.0m/s initial speed

g = 9.80m/s²

0 = 45.0 + 20×t –1/2×9.8×t²

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Solving quadratically or by using a calculator,

t = 5.69s and –1.61s byt time cannot be negative so t = 5.69s

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3 0
3 years ago
An inductor is connected to an AC power supply having a maximum output voltage of 3.00 V at a frequency of 280 Hz. What inductan
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Answer:

L = 0.48 H

Explanation:

let L be the inductance, Irms be the rms current, Vrms be the rms voltage and Vmax  be the maximum voltage and XL be the be the reactance of the inductor.

Vrms = Vmax/(√2)

         = (3.00)/(√2)

         = 2.121 V

then:

XL = Vrms/I  

     = (2.121)/(2.50×10^-3)

     = 848.528 V/A

that is L = XL/(2×π×f)

              = (848.528)/(2×π×(280))

              = 0.482 H

Therefore, the inductance needed to kepp the rms current less than 2.50mA is 0.482 H.

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