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mestny [16]
3 years ago
5

How is it technically correct to say that a car making a u-turn can have a constant speed but cannot have a constant velocity?

Physics
1 answer:
saw5 [17]3 years ago
5 0

During the "U" part of the turn, the car would follow an approximately circular path, and if it's moving at a constant speed, it would have to accelerate toward the center of the circle in order to change its direction.

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A certain radar installation tracks airplanes by transmitting electromagnetic radiation of wavelength 4.0 cm.
Anna35 [415]

the wavelength equation is

speed (of light in this case)= wavelength (m) x frequency

3x10^8m/s / .07m = f

frequency= 4 285 714 286 hertz

 

 

 

b) Total distance= 4.8 km (4,800 m)

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d=st

t= d/s

t= 4,800 m/3x10^8m/s

<span>t= 1x10^-5 seconds</span>

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3 years ago
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Solve the equation of motion, using Newton's 1 Law F 0, for a general case of M the mass of the wooden block and u, being the co
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Answer:

Explanation:

The first thing to have to make a diagram where we indicate the forces acting on the block, see attached. We have the following

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  The friction force (fr) that opposes the movement

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  The normal (N) which is the reaction to the support of the body and is perpendicular to the surface

We write a reference system where one axis is parallel to the surface (x axis) and the other is perpendicular to it (Y axis) we decompose the forces on these axes, we see that the only force we have to decompose r is the weight

             sin θ  = Wx / W       ⇒      Wx = W sin θ

             cos θ = Xy / W        ⇒      Wy = Wcos θ

We write Newton's equations for each axis

             N- Wy = 0

             F -fr -Wx = m a          (1)

The expression for the friction force is

             fr = μ N

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             N = W cos θ

             fr = μ mg cosT

   

We hope, we simplify the acceleration of equation 1

           a = F - μ mg cos θ -mg sinθ

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This is the general equation for movement.

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3 years ago
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8 0
4 years ago
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It is elastic energy
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20 PTS!
klemol [59]
  • its acceleration is zeo

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